7
2010

8

01

87 11 7

9
4

8
4

1

B( 

5
3

; 2)

A(

197122908
1
2
1
x
x
3
2
1
6

5
; 2)
3

1
0
2


1
6

(O, I , ...
6

ˆ
BEC  40

ˆ
xAB  80

04

( xy ) //( BE )

ˆ
CBE

1

ˆ
BCE
ˆ
CEt  60

D

Ay 

Et 

2

( Et ) //( AB )
ˆ
A DE
...
12
2009

7

01

87 11 7

11
4

01

10000 10

10

7

10

1108

608
()

3cm
ˆ
yO z

ˆ
xO y

70

110

3

3cm

ˆ
xOy  70...
x  y  100

A

7
ˆ
xO y

OA

A

( )

OA  3cm

2

04
1

Ox 

A

( )

(Oy )

ˆ
AOE  40

( )

E

2

ˆ
yO E

(OE )

A...
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Devoir+de+synthèse+n°1++ +math+-+8ème+(2010-2011)+mr+arfaoui+khaled

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Devoir+de+synthèse+n°1++ +math+-+8ème+(2010-2011)+mr+arfaoui+khaled

  1. 1. 7 2010 8 01 87 11 7 9 4 8 4 1 B(  5 3 ; 2) A( 197122908 1 2 1 x x 3 2 1 6 5 ; 2) 3 1 0 2  1 6 (O, I , J ) 3 (OI ) (OJ ) ˆ BAC 01 ˆ A ABC  50 130 O ABC 4 50 80 4 02 1 a 135 1 135 2   ( ) 111 3 111 5 2 5 7 3 b  0,35  (1  )  (  ) 2 20 2 6 y x 2 7 1  ( x  y  )  ( x  y)  5 5 2 1 A x 2 10 x A 3 2 A x 3 03 A x 1 2 3
  2. 2. 6 ˆ BEC  40 ˆ xAB  80 04 ( xy ) //( BE ) ˆ CBE 1 ˆ BCE ˆ CEt  60 D Ay  Et  2 ( Et ) //( AB ) ˆ A DE 3
  3. 3. 12 2009 7 01 87 11 7 11 4 01 10000 10 10 7 10 1108 608 () 3cm ˆ yO z ˆ xO y 70 110 3 3cm ˆ xOy  70 ˆ yO z 4 2 598 ( ) 3cm 10 1 254  x  852 x 3cm 5 3 4 20 5 02 1 d  17 0 c 1 27 b2 5 a  25  10  (7  5)  145 2 z  81 3 7 7 x  49 y 5 5 4 y x 03 A  2(5 x  y )  x  9 y A  11x  11y 1
  4. 4. x  y  100 A 7 ˆ xO y OA A ( ) OA  3cm 2 04 1 Ox  A ( ) (Oy ) ˆ AOE  40 ( ) E 2 ˆ yO E (OE ) A E ( ) ˆ EOF (OF ) 3 ( ) (OE ) ˆ AOF  40 H A 4 F Ox  K AH  AK

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