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Hari Prasad 
Assistant Professor 
MVJCE-Bangalore 
Hari Prasad
Learning objectives 
• After the chapter is completed, you will be able 
to answer: 
• Difference between crystalline and 
noncrystalline structures 
• Different crystal systems and crystal structures 
• Atomic packing factors of different cubic crystal 
systems 
• Difference between unit cell and primitive cell 
• Difference between single crystals and poly 
crystals 
Hari Prasad
What is space lattice? 
• Space lattice is the distribution of points in 
3D in such a way that every point has 
identical surroundings, i.e., it is an infinite 
array of points in three dimensions in 
which every point has surroundings 
identical to every other point in the array. 
Hari Prasad
Common materials: with various ‘viewpoints’ 
Glass: amorphous 
Ceramics 
Crystal 
Graphite 
Metals Polymers
Common materials: examples 
 Metals and alloys  Cu, Ni, Fe, NiAl (intermetallic compound), Brass (Cu-Zn alloys) 
 Ceramics (usually oxides, nitrides, carbides)  Alumina (Al2O3), Zirconia (Zr2O3) 
 Polymers (thermoplasts, thermosets) (Elastomers) Polythene, Polyvinyl chloride, Polypropylene 
Based on Electrical Conduction 
 Conductors  Cu, Al, NiAl 
 Semiconductors  Ge, Si, GaAs 
 Insulators  Alumina, Polythene* 
Based on Ductility 
 Ductile  Metals, Alloys 
 Brittle  Ceramics, Inorganic Glasses, Ge, Si 
* some special polymers could be conducting
 The broad scientific and technological segments of Materials Science are shown 
MATERIALS SCIENCE & ENGINEERING 
PHYSICAL MECHANICAL ELECTRO-CHEMICAL 
TECHNOLOGICAL 
• Extractive 
• Casting 
• Metal Forming 
•Welding 
• Powder Metallurgy 
• Machining 
• Structure 
• Physical 
Properties 
Science of Metallurgy 
• Deformation 
Behaviour 
• Thermodynamics 
• Chemistry 
• Corrosion 
in the diagram below. 
 To gain a comprehensive understanding of materials science, all these aspects 
have to be studied.
Crystal = Lattice + 
Motif 
Motif or Basis: 
typically an atom or a group of atoms associated with each lattice point 
Lattice  the underlying periodicity of the crystal 
Basis  Entity associated with each lattice points 
Lattice  how to repeat 
Motif  what to repeat 
Definition 1 
Crystal 
Translationally periodic 
arrangement of motifs 
Lattice 
Translationally periodic 
arrangement of points
Hari Prasad
Space Lattice 
A lattice is also called a Space Lattice 
An array of points such that every point has 
identical surroundings 
 In Euclidean space  infinite array 
 We can have 1D, 2D or 3D arrays (lattices) 
or 
Translationally periodic arrangement of points in space is called a lattice
Unit cell: A unit cell is the sub-division of the 
space lattice that still retains the overall 
characteristics of the space lattice. 
Primitive cell: the smallest possible unit cell of a 
lattice, having lattice points at each of its eight 
vertices only. 
A primitive cell is a minimum volume cell 
corresponding to a single lattice point of a structure 
with translational symmetry in 2 dimensions, 3 
dimensions, or other dimensions. 
A lattice can be characterized by the geometry of its 
primitive cell. 
Hari Prasad
Materials and Packing 
Crystalline materials... 
• atoms pack in periodic, 3D arrays 
-metals 
-many ceramics 
-some polymers 
Non-crystalline materials... 
• atoms have no periodic packing 
-complex structures 
-rapid cooling 
crystalline SiO2 (Quartz) 
"Amorphous" = Noncrystalline 
Si Oxygen 
• typical of: 
• occurs for: 
noncrystalline SiO2 (Glass) 
Hari Prasad
Crystal Systems 
Unit cell: smallest repetitive volume which contains 
the complete lattice pattern of a crystal. 
7 crystal systems 
14 crystal lattices 
a, b, and c are the lattice constants 
Hari Prasad
The Unite Cell is the smallest group of atom showing 
the characteristic lattice structure of a particular metal. 
It is the building block of a single crystal. 
A single crystal can have many unit cells. 
Hari Prasad
Crystal systems 
Cubic Three equal axes, mutually perpendicular 
a=b=c ===90˚ 
Tetragonal Three perpendicular axes, only two equal 
a=b≠c ===90˚ 
Hexagonal Three equal coplanar axes at 120˚ and a fourth unequal 
axis perpendicular to their plane 
a=b≠c == 90˚ =120˚ 
Rhombohedral Three equal axes, not at right angles 
a=b=c ==≠90˚ 
Orthorhombic Three unequal axes, all perpendicular 
a≠b≠c ===90˚ 
Monoclinic Three unequal axes, one of which is perpendicular to the 
other two 
a≠b≠c ==90˚≠  
Triclinic Three unequal axes, no two of which are perpendicular 
a≠b≠c ≠ ≠≠90˚ 
Hari Prasad
Some engineering applications require single crystals: 
Hari Prasad 
--diamond single 
crystals for abrasives 
--turbine blades
What is coordination number? 
• The coordination number of a central atom in a 
crystal is the number of its nearest neighbours. 
What is lattice parameter? 
• The lattice constant, or lattice parameter, refers 
to the physical dimension of unit cells in a crystal 
lattice. 
• Lattices in three dimensions generally have 
three lattice constants, referred to as a, b, and 
c. 
Hari Prasad
Simple Cubic Structure (SC) 
• Rare due to low packing density (only Po has this structure) 
• Close-packed directions are cube edges. 
• Coordination # = 6 
(# nearest neighbors) 
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Body Centered Cubic Structure (BCC) 
• Atoms touch each other along cube diagonals. 
--Note: All atoms are identical; the center atom is shaded 
differently only for ease of viewing. 
ex: Cr, W, Fe (), Tantalum, Molybdenum 
• Coordination # = 8 
2 atoms/unit cell: 1 center + 8 corners x 1/8 
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Atomic Packing Factor: BCC 
a 
APF = 
4 
3 
Close-packed directions: 
p ( 3 a/4 ) 3 
2 
atoms 
length = 4R = 
volume 
unit cell atom 
a 3 
volume 
unit cell 
3 a 
• APF for a body-centered cubic structure = 0.68 
a 
R 
2 a 
3 a 
Hari Prasad
Face Centered Cubic Structure (FCC) 
• Atoms touch each other along face diagonals. 
--Note: All atoms are identical; the face-centered atoms are shaded 
differently only for ease of viewing. 
ex: Al, Cu, Au, Pb, Ni, Pt, Ag 
• Coordination # = 12 
4 atoms/unit cell: 6 face x 1/2 + 8 corners x 1/8 
Hari Prasad
Hari Prasad
Atomic Packing Factor: FCC 
• APF for a face-centered cubic structure = 0.74 
maximum achievable APF 
Close-packed directions: 
length = 4R = 2 a 
atoms 
unit cell atom 
APF = 
4 
3 
4 p ( 2a/4)3 
volume 
a3 
volume 
unit cell 
Unit cell contains: 
6 x 1/2 + 8 x 1/8 
= 4 atoms/unit cell 
2 a 
a 
Hari Prasad
FCC Stacking Sequence 
• ABCABC... Stacking Sequence 
• 2D Projection 
A sites 
C 
B B 
B 
B B 
B B 
C sites 
C C 
A 
B sites 
• FCC Unit Cell 
A 
B 
C
Putting atoms in the B position in the II layer and in C positions in the III layer we get 
a stacking sequence  ABC ABC ABC….  The CCP (FCC) crystal 
+ + 
A B 
FCC 
= 
A 
B 
C 
A 
B 
C 
C
Hexagonal Close-Packed Structure 
• ABAB... Stacking Sequence 
• 3D Projection • 2D Projection 
c 
a 
• Coordination # = 12 
• APF = 0.74 
(HCP) 
Top layer 
Middle layer 
6 atoms/unit cell 
ex: Cd, Mg, Ti, Zn 
• c/a = 1.633 
A sites 
B sites 
A sites Bottom layer 
Hari Prasad
APF for HCP 
a Area of triangle = 
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c 
a 
A sites 
B sites 
A sites 
C=1.633a 
Number of atoms in HCP unit cell= 
(12*1/6)+(2*1/2)+3=6atoms 
Vol.of HCP unit cell= 
area of the hexagonal face X height of the hexagonal 
Area of the hexagonal face=area of each triangle X6 
h 
a 
풃풉 
ퟐ 
= 
풂풉 
ퟐ 
= 
ퟏ 
ퟐ 
풂. 
풂 ퟑ 
ퟐ 
Area of hexagon = ퟔ. 
풂ퟐ ퟑ 
ퟒ 
Volume of HCP= ퟔ. 
풂ퟐ ퟑ 
ퟒ 
. 퐂 = ퟔ. 
풂ퟐ ퟑ 
ퟒ 
. ퟏ. ퟔퟑퟑ퐚 
APF= 6∗ 
ퟒ흅풓ퟑ 
ퟑ 
/( 
ퟑ 
ퟒ 
∗ ퟔ ∗ ퟏ. ퟔퟑퟑ ∗ 퐚ퟑ) 
a=2r 
APF =0.74
SC-coordination number 
Hari Prasad 
6
Hari Prasad 
• Coordination # = 6 
(# nearest neighbors)
BCC-coordination number 
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8
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FCC-coordination number 
4+4+4=12 
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HCP-coordination number 
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3+6+3=12
Theoretical Density, r 
Density = r = 
Massof AtomsinUnitCell 
TotalVolumeofUnitCell 
n A 
VC NA 
r = 
where n = number of atoms/unit cell 
A = atomic weight 
VC = Volume of unit cell = a3 for cubic 
NA = Avogadro’s number 
= 6.023 x 1023 atoms/mol 
Hari Prasad
Theoretical Density, r 
• Ex: Cr (BCC) 
A = 52.00 g/mol 
R = 0.125 nm 
n = 2 
a = 4R/ 3 = 0.2887 nm 
rtheoretical 
ractual 
a 
R 
r = 
a 3 
2 52.00 
atoms 
unit cell 
g 
mol 
volume atoms 
unit cell 
mol 
6.023 x 1023 
= 7.18 g/cm3 
= 7.19 g/cm3 
Hari Prasad
Polymorphism 
• Two or more distinct crystal structures for the same 
material (allotropy/polymorphism) 
titanium 
, -Ti 
carbon 
diamond, graphite 
iron system 
BCC 
FCC 
BCC 
1538ºC 
-Fe 
1394ºC 
-Fe 
912ºC 
-Fe 
liquid 
Hari Prasad
Miller indices 
Miller indices: defined as the reciprocals of 
the intercepts made by the plane on the three 
axes. 
Hari Prasad
Procedure for finding Miller indices 
Determine the intercepts 
of the plane along the axes 
X,Y and Z in terms of the 
lattice constants a, b and c. 
Hari Prasad 
Step 1
Determine the 
reciprocals of these 
numbers. 
Hari Prasad 
Step 2
Find the least common 
denominator (lcd) 
and multiply each by 
this lcd 
Hari Prasad 
Step 3
The result is written in 
parenthesis. 
This is called the `Miller 
Indices’ of the plane in 
the form (h k l). 
Hari Prasad 
Step 4
(2,0,0) 
Miller Indices for planes 
(0,3,0) 
(0,0,1) 
 Find intercepts along axes → 2 3 1 
 Take reciprocal → 1/2 1/3 1 
 Convert to smallest integers in the same ratio → 3 2 6 
 Enclose in parenthesis → (326)
Plane ABC has intercepts of 2 units 
along X-axis, 3 units along Y-axis and 2 
units along Z-axis. 
Hari Prasad 
X 
Z 
Y 
A 
C 
B
DETERMINATION OF ‘MILLER INDICES’ 
Step 1: The intercepts are 2, 3 and 2 on the three 
axes. 
Step 2: The reciprocals are 1/2, 1/3 and 1/2. 
Step 3: The least common denominator is ‘6’. 
Multiplying each reciprocal by lcd, 
we get, 3,2 and 3. 
Step 4:Hence Miller indices for the plane ABC is (3 
2 3) 
Hari Prasad
IMPORTANT FEATURES OF MILLER INDICES 
For the cubic crystal especially, the important features of 
Miller indices are, 
 A plane which is parallel to any one of the co-ordinate 
axes has an intercept of infinity (). 
 Therefore the Miller index for that axis is zero; i.e. for an 
intercept at infinity, the corresponding index is zero. 
 A plane passing through the origin is defined in terms 
of a parallel plane having non zero intercepts. 
 All equally spaced parallel planes have same ‘Miller 
indices’ i.e. The Miller indices do not only define a 
particular plane but also a set of parallel planes. 
 Thus the planes whose intercepts are 1, 1,1; 2,2,2; -3,-3,-3 
etc., are all represented by the same set of Miller 
indices. 
Hari Prasad
Worked Example: 
 Calculate the miller indices for the plane with intercepts 2a, - 3b 
and 4c the along the crystallographic axes. 
 The intercepts are 2, - 3 and 4 
 Step 1: The intercepts are 2, -3 and 4 along the 3 axes 
 Step 2: The reciprocals are 
 Step 3: The least common denominator is 12. 
Multiplying each reciprocal by lcd, we get 6 -4 and 3 
Step 4: Hence the Miller indices for the plane is 6 4 3 
Hari Prasad
Intercepts → 1   
Plane → (100) 
Family → {100} → 3 
Intercepts → 1 1  
Plane → (110) 
Family → {110} → 6 
Intercepts → 1 1 1 
Plane → (111) 
Family → {111} → 8 
(Octahedral plane)
Hari Prasad 
Miller Indices : (100)
Intercepts : a , a , ∞ 
Fractional intercepts : 1 , 1 , ∞ 
Miller Indices : (110) 
Hari Prasad
Intercepts : a , a , a 
Fractional intercepts : 1 , 1 , 1 
Miller Indices : (111) 
Hari Prasad
Intercepts : ½ a , a , ∞ 
Fractional intercepts : ½ , 1 , ∞ 
Miller Indices : (210) 
Hari Prasad
Hari Prasad
Hari Prasad 
(101) 
Z 
Y 
X
Hari Prasad 
(122)
Hari Prasad 
(211)
Crystallographic Directions 
 The crystallographic directions are fictitious 
lines linking nodes (atoms, ions or molecules) of 
a crystal. 
 Similarly, the crystallographic planes are 
fictitious planes linking nodes. 
 The length of the vector projection on each of the 
three axes is determined; these are measured in 
terms of the unit cell dimensions a, b, and c. 
Hari Prasad
 To find the Miller indices of a direction, 
Choose a perpendicular plane to that direction. 
 Find the Miller indices of that perpendicular 
Hari Prasad 
plane. 
 The perpendicular plane and the direction have 
the same Miller indices value. 
 Therefore, the Miller indices of the 
perpendicular plane is written within a square 
bracket to represent the Miller indices of the 
direction like [ ].
Summary of notations 
Symbol 
Alternate 
symbols 
Directio 
n 
[ ] [uvw] → Particular direction 
< > <uvw> [[ ]] → Family of directions 
Plane 
( ) (hkl) → Particular plane 
{ } {hkl} (( )) → Family of planes 
Point 
. . .xyz. [[ ]] → Particular point 
: : :xyz: → Family of point 
*A family is also referred to as a symmetrical set
For each of the three axes, there will exist 
both positive and negative coordinates. 
Thus negative indices are also possible, 
which are represented by a bar over 
the appropriate index. For example, the 1 
The above image shows [100], [110], and [111] directions within a 
unit cell 
Hari Prasad
The vector, as drawn, passes through the origin of the coordinate system, 
and therefore no translation is necessary. Projections of this vector onto the 
x, y, and z axes are, respectively,1/2, b, and 0c, which become 1/2, 1, and 0 in 
terms of the unit cell parameters (i.e., when the a, b, and c are dropped). 
Reduction of these numbers to the lowest set of integers is accompanied by 
multiplication of each by the factor 2.This yields the integers 1, 2, and 0, 
which are then enclosed in brackets as [120]. 
Hari Prasad
Hari Prasad
Worked Example 
 Find the angle between the directions [2 1 1] and [1 1 2] in a 
u u v v w w 
  
½ ½ 
Hari Prasad 
cubic crystal. 
The two directions are [2 1 1] and [1 1 2] 
We know that the angle between the two directions, 
1 2 1 2 1 2 
2 2 2 2 2 2 
1 1 1 2 2 2 
cos 
(u v w ) (u v w ) 
  
    
In this case, u1 = 2, v1 = 1, w1 = 1, Type equation here.u2 = 1, 
(2  1)  (1  1)  (1  
2) 5 
    
Hari Prasad 
v2 = 1, w2 = 2 
(or) cos  = 0.833 
 = 35° 3530. 
2 2 2 2 2 2 
cos 
2  1  l  1  1  
2 6
Reference 
http://core.materials.ac.uk/repository/doitpoms/tlp/miller_indices/indexing_a_pla 
ne_embed.swf 
http://core.materials.ac.uk/repository/doitpoms/tlp/miller_indices/drawing_lattice 
_planes.swf 
http://core.materials.ac.uk/repository/doitpoms/tlp/miller_indices/miller.swf 
Hari Prasad

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Crystal structures in material science

  • 1. Hari Prasad Assistant Professor MVJCE-Bangalore Hari Prasad
  • 2. Learning objectives • After the chapter is completed, you will be able to answer: • Difference between crystalline and noncrystalline structures • Different crystal systems and crystal structures • Atomic packing factors of different cubic crystal systems • Difference between unit cell and primitive cell • Difference between single crystals and poly crystals Hari Prasad
  • 3. What is space lattice? • Space lattice is the distribution of points in 3D in such a way that every point has identical surroundings, i.e., it is an infinite array of points in three dimensions in which every point has surroundings identical to every other point in the array. Hari Prasad
  • 4. Common materials: with various ‘viewpoints’ Glass: amorphous Ceramics Crystal Graphite Metals Polymers
  • 5. Common materials: examples  Metals and alloys  Cu, Ni, Fe, NiAl (intermetallic compound), Brass (Cu-Zn alloys)  Ceramics (usually oxides, nitrides, carbides)  Alumina (Al2O3), Zirconia (Zr2O3)  Polymers (thermoplasts, thermosets) (Elastomers) Polythene, Polyvinyl chloride, Polypropylene Based on Electrical Conduction  Conductors  Cu, Al, NiAl  Semiconductors  Ge, Si, GaAs  Insulators  Alumina, Polythene* Based on Ductility  Ductile  Metals, Alloys  Brittle  Ceramics, Inorganic Glasses, Ge, Si * some special polymers could be conducting
  • 6.  The broad scientific and technological segments of Materials Science are shown MATERIALS SCIENCE & ENGINEERING PHYSICAL MECHANICAL ELECTRO-CHEMICAL TECHNOLOGICAL • Extractive • Casting • Metal Forming •Welding • Powder Metallurgy • Machining • Structure • Physical Properties Science of Metallurgy • Deformation Behaviour • Thermodynamics • Chemistry • Corrosion in the diagram below.  To gain a comprehensive understanding of materials science, all these aspects have to be studied.
  • 7. Crystal = Lattice + Motif Motif or Basis: typically an atom or a group of atoms associated with each lattice point Lattice  the underlying periodicity of the crystal Basis  Entity associated with each lattice points Lattice  how to repeat Motif  what to repeat Definition 1 Crystal Translationally periodic arrangement of motifs Lattice Translationally periodic arrangement of points
  • 9. Space Lattice A lattice is also called a Space Lattice An array of points such that every point has identical surroundings  In Euclidean space  infinite array  We can have 1D, 2D or 3D arrays (lattices) or Translationally periodic arrangement of points in space is called a lattice
  • 10. Unit cell: A unit cell is the sub-division of the space lattice that still retains the overall characteristics of the space lattice. Primitive cell: the smallest possible unit cell of a lattice, having lattice points at each of its eight vertices only. A primitive cell is a minimum volume cell corresponding to a single lattice point of a structure with translational symmetry in 2 dimensions, 3 dimensions, or other dimensions. A lattice can be characterized by the geometry of its primitive cell. Hari Prasad
  • 11. Materials and Packing Crystalline materials... • atoms pack in periodic, 3D arrays -metals -many ceramics -some polymers Non-crystalline materials... • atoms have no periodic packing -complex structures -rapid cooling crystalline SiO2 (Quartz) "Amorphous" = Noncrystalline Si Oxygen • typical of: • occurs for: noncrystalline SiO2 (Glass) Hari Prasad
  • 12. Crystal Systems Unit cell: smallest repetitive volume which contains the complete lattice pattern of a crystal. 7 crystal systems 14 crystal lattices a, b, and c are the lattice constants Hari Prasad
  • 13. The Unite Cell is the smallest group of atom showing the characteristic lattice structure of a particular metal. It is the building block of a single crystal. A single crystal can have many unit cells. Hari Prasad
  • 14. Crystal systems Cubic Three equal axes, mutually perpendicular a=b=c ===90˚ Tetragonal Three perpendicular axes, only two equal a=b≠c ===90˚ Hexagonal Three equal coplanar axes at 120˚ and a fourth unequal axis perpendicular to their plane a=b≠c == 90˚ =120˚ Rhombohedral Three equal axes, not at right angles a=b=c ==≠90˚ Orthorhombic Three unequal axes, all perpendicular a≠b≠c ===90˚ Monoclinic Three unequal axes, one of which is perpendicular to the other two a≠b≠c ==90˚≠  Triclinic Three unequal axes, no two of which are perpendicular a≠b≠c ≠ ≠≠90˚ Hari Prasad
  • 15. Some engineering applications require single crystals: Hari Prasad --diamond single crystals for abrasives --turbine blades
  • 16. What is coordination number? • The coordination number of a central atom in a crystal is the number of its nearest neighbours. What is lattice parameter? • The lattice constant, or lattice parameter, refers to the physical dimension of unit cells in a crystal lattice. • Lattices in three dimensions generally have three lattice constants, referred to as a, b, and c. Hari Prasad
  • 17. Simple Cubic Structure (SC) • Rare due to low packing density (only Po has this structure) • Close-packed directions are cube edges. • Coordination # = 6 (# nearest neighbors) Hari Prasad
  • 21. Body Centered Cubic Structure (BCC) • Atoms touch each other along cube diagonals. --Note: All atoms are identical; the center atom is shaded differently only for ease of viewing. ex: Cr, W, Fe (), Tantalum, Molybdenum • Coordination # = 8 2 atoms/unit cell: 1 center + 8 corners x 1/8 Hari Prasad
  • 24. Atomic Packing Factor: BCC a APF = 4 3 Close-packed directions: p ( 3 a/4 ) 3 2 atoms length = 4R = volume unit cell atom a 3 volume unit cell 3 a • APF for a body-centered cubic structure = 0.68 a R 2 a 3 a Hari Prasad
  • 25. Face Centered Cubic Structure (FCC) • Atoms touch each other along face diagonals. --Note: All atoms are identical; the face-centered atoms are shaded differently only for ease of viewing. ex: Al, Cu, Au, Pb, Ni, Pt, Ag • Coordination # = 12 4 atoms/unit cell: 6 face x 1/2 + 8 corners x 1/8 Hari Prasad
  • 27. Atomic Packing Factor: FCC • APF for a face-centered cubic structure = 0.74 maximum achievable APF Close-packed directions: length = 4R = 2 a atoms unit cell atom APF = 4 3 4 p ( 2a/4)3 volume a3 volume unit cell Unit cell contains: 6 x 1/2 + 8 x 1/8 = 4 atoms/unit cell 2 a a Hari Prasad
  • 28. FCC Stacking Sequence • ABCABC... Stacking Sequence • 2D Projection A sites C B B B B B B B C sites C C A B sites • FCC Unit Cell A B C
  • 29. Putting atoms in the B position in the II layer and in C positions in the III layer we get a stacking sequence  ABC ABC ABC….  The CCP (FCC) crystal + + A B FCC = A B C A B C C
  • 30. Hexagonal Close-Packed Structure • ABAB... Stacking Sequence • 3D Projection • 2D Projection c a • Coordination # = 12 • APF = 0.74 (HCP) Top layer Middle layer 6 atoms/unit cell ex: Cd, Mg, Ti, Zn • c/a = 1.633 A sites B sites A sites Bottom layer Hari Prasad
  • 31. APF for HCP a Area of triangle = Hari Prasad c a A sites B sites A sites C=1.633a Number of atoms in HCP unit cell= (12*1/6)+(2*1/2)+3=6atoms Vol.of HCP unit cell= area of the hexagonal face X height of the hexagonal Area of the hexagonal face=area of each triangle X6 h a 풃풉 ퟐ = 풂풉 ퟐ = ퟏ ퟐ 풂. 풂 ퟑ ퟐ Area of hexagon = ퟔ. 풂ퟐ ퟑ ퟒ Volume of HCP= ퟔ. 풂ퟐ ퟑ ퟒ . 퐂 = ퟔ. 풂ퟐ ퟑ ퟒ . ퟏ. ퟔퟑퟑ퐚 APF= 6∗ ퟒ흅풓ퟑ ퟑ /( ퟑ ퟒ ∗ ퟔ ∗ ퟏ. ퟔퟑퟑ ∗ 퐚ퟑ) a=2r APF =0.74
  • 33. Hari Prasad • Coordination # = 6 (# nearest neighbors)
  • 38. HCP-coordination number Hari Prasad 3+6+3=12
  • 39. Theoretical Density, r Density = r = Massof AtomsinUnitCell TotalVolumeofUnitCell n A VC NA r = where n = number of atoms/unit cell A = atomic weight VC = Volume of unit cell = a3 for cubic NA = Avogadro’s number = 6.023 x 1023 atoms/mol Hari Prasad
  • 40. Theoretical Density, r • Ex: Cr (BCC) A = 52.00 g/mol R = 0.125 nm n = 2 a = 4R/ 3 = 0.2887 nm rtheoretical ractual a R r = a 3 2 52.00 atoms unit cell g mol volume atoms unit cell mol 6.023 x 1023 = 7.18 g/cm3 = 7.19 g/cm3 Hari Prasad
  • 41. Polymorphism • Two or more distinct crystal structures for the same material (allotropy/polymorphism) titanium , -Ti carbon diamond, graphite iron system BCC FCC BCC 1538ºC -Fe 1394ºC -Fe 912ºC -Fe liquid Hari Prasad
  • 42. Miller indices Miller indices: defined as the reciprocals of the intercepts made by the plane on the three axes. Hari Prasad
  • 43. Procedure for finding Miller indices Determine the intercepts of the plane along the axes X,Y and Z in terms of the lattice constants a, b and c. Hari Prasad Step 1
  • 44. Determine the reciprocals of these numbers. Hari Prasad Step 2
  • 45. Find the least common denominator (lcd) and multiply each by this lcd Hari Prasad Step 3
  • 46. The result is written in parenthesis. This is called the `Miller Indices’ of the plane in the form (h k l). Hari Prasad Step 4
  • 47. (2,0,0) Miller Indices for planes (0,3,0) (0,0,1)  Find intercepts along axes → 2 3 1  Take reciprocal → 1/2 1/3 1  Convert to smallest integers in the same ratio → 3 2 6  Enclose in parenthesis → (326)
  • 48. Plane ABC has intercepts of 2 units along X-axis, 3 units along Y-axis and 2 units along Z-axis. Hari Prasad X Z Y A C B
  • 49. DETERMINATION OF ‘MILLER INDICES’ Step 1: The intercepts are 2, 3 and 2 on the three axes. Step 2: The reciprocals are 1/2, 1/3 and 1/2. Step 3: The least common denominator is ‘6’. Multiplying each reciprocal by lcd, we get, 3,2 and 3. Step 4:Hence Miller indices for the plane ABC is (3 2 3) Hari Prasad
  • 50. IMPORTANT FEATURES OF MILLER INDICES For the cubic crystal especially, the important features of Miller indices are,  A plane which is parallel to any one of the co-ordinate axes has an intercept of infinity ().  Therefore the Miller index for that axis is zero; i.e. for an intercept at infinity, the corresponding index is zero.  A plane passing through the origin is defined in terms of a parallel plane having non zero intercepts.  All equally spaced parallel planes have same ‘Miller indices’ i.e. The Miller indices do not only define a particular plane but also a set of parallel planes.  Thus the planes whose intercepts are 1, 1,1; 2,2,2; -3,-3,-3 etc., are all represented by the same set of Miller indices. Hari Prasad
  • 51. Worked Example:  Calculate the miller indices for the plane with intercepts 2a, - 3b and 4c the along the crystallographic axes.  The intercepts are 2, - 3 and 4  Step 1: The intercepts are 2, -3 and 4 along the 3 axes  Step 2: The reciprocals are  Step 3: The least common denominator is 12. Multiplying each reciprocal by lcd, we get 6 -4 and 3 Step 4: Hence the Miller indices for the plane is 6 4 3 Hari Prasad
  • 52. Intercepts → 1   Plane → (100) Family → {100} → 3 Intercepts → 1 1  Plane → (110) Family → {110} → 6 Intercepts → 1 1 1 Plane → (111) Family → {111} → 8 (Octahedral plane)
  • 53. Hari Prasad Miller Indices : (100)
  • 54. Intercepts : a , a , ∞ Fractional intercepts : 1 , 1 , ∞ Miller Indices : (110) Hari Prasad
  • 55. Intercepts : a , a , a Fractional intercepts : 1 , 1 , 1 Miller Indices : (111) Hari Prasad
  • 56. Intercepts : ½ a , a , ∞ Fractional intercepts : ½ , 1 , ∞ Miller Indices : (210) Hari Prasad
  • 61. Crystallographic Directions  The crystallographic directions are fictitious lines linking nodes (atoms, ions or molecules) of a crystal.  Similarly, the crystallographic planes are fictitious planes linking nodes.  The length of the vector projection on each of the three axes is determined; these are measured in terms of the unit cell dimensions a, b, and c. Hari Prasad
  • 62.  To find the Miller indices of a direction, Choose a perpendicular plane to that direction.  Find the Miller indices of that perpendicular Hari Prasad plane.  The perpendicular plane and the direction have the same Miller indices value.  Therefore, the Miller indices of the perpendicular plane is written within a square bracket to represent the Miller indices of the direction like [ ].
  • 63. Summary of notations Symbol Alternate symbols Directio n [ ] [uvw] → Particular direction < > <uvw> [[ ]] → Family of directions Plane ( ) (hkl) → Particular plane { } {hkl} (( )) → Family of planes Point . . .xyz. [[ ]] → Particular point : : :xyz: → Family of point *A family is also referred to as a symmetrical set
  • 64. For each of the three axes, there will exist both positive and negative coordinates. Thus negative indices are also possible, which are represented by a bar over the appropriate index. For example, the 1 The above image shows [100], [110], and [111] directions within a unit cell Hari Prasad
  • 65. The vector, as drawn, passes through the origin of the coordinate system, and therefore no translation is necessary. Projections of this vector onto the x, y, and z axes are, respectively,1/2, b, and 0c, which become 1/2, 1, and 0 in terms of the unit cell parameters (i.e., when the a, b, and c are dropped). Reduction of these numbers to the lowest set of integers is accompanied by multiplication of each by the factor 2.This yields the integers 1, 2, and 0, which are then enclosed in brackets as [120]. Hari Prasad
  • 67. Worked Example  Find the angle between the directions [2 1 1] and [1 1 2] in a u u v v w w   ½ ½ Hari Prasad cubic crystal. The two directions are [2 1 1] and [1 1 2] We know that the angle between the two directions, 1 2 1 2 1 2 2 2 2 2 2 2 1 1 1 2 2 2 cos (u v w ) (u v w )       
  • 68. In this case, u1 = 2, v1 = 1, w1 = 1, Type equation here.u2 = 1, (2  1)  (1  1)  (1  2) 5     Hari Prasad v2 = 1, w2 = 2 (or) cos  = 0.833  = 35° 3530. 2 2 2 2 2 2 cos 2  1  l  1  1  2 6
  • 69. Reference http://core.materials.ac.uk/repository/doitpoms/tlp/miller_indices/indexing_a_pla ne_embed.swf http://core.materials.ac.uk/repository/doitpoms/tlp/miller_indices/drawing_lattice _planes.swf http://core.materials.ac.uk/repository/doitpoms/tlp/miller_indices/miller.swf Hari Prasad