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Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
Penambahan pecahan
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Penambahan pecahan

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  • 1. Pecahan
  • 2. Pengangka Penyebut
  • 3.  
  • 4.  
  • 5.  
  • 6.  
  • 7. = + = + Menambah dua pecahan wajar penyebut yang sama Contoh 1
  • 8. = + = + Contoh 2
  • 9. = + = + Contoh 3
  • 10. = + = + Kamu ada idea untuk dapatkan jawapan ? Menambah dua pecahan wajar penyebut yang tidak sama
  • 11. Langkah Penyelesaian
  • 12. = + = + = + Menambah dua pecahan wajar penyebut yang tidak sama Contoh 1
  • 13. = = + = + Contoh 2 +
  • 14. = = + = + Contoh 3 +
  • 15. = = + = + Contoh 4 +
  • 16. = = + = + Contoh 5 +
  • 17. Latihan
  • 18. + 2 6 12 + + + 8 2 4 3 6 9 4 8 16
  • 19. = + = + = + Menambah dua pecahan wajar penyebut yang berbeza
  • 20. Penyelesaian Masalah Soalan Latihan Pecahan
  • 21. Lina’s mother used of 2kg of sugar to bake a cake . How much did she use? Give your answer in g. Ibu Lina menggunakan daripada 2 kg gula untuk membuat kek. Berapa banyakkah gula yang ibu Lina gunakan untuk membuat kek itu ? Berikan jawapan dalam g. Soalan 1 2Kg / 2000g 500 500 500 500 Use = 500 g / 0.5 kg
  • 22. A bottle contains 1.5l of water. Of the water is spilt. How much is the volume, in ml, of water is left in the bottle ? Isipadu air dalam botol ialah 1.5l. Daripada air itu tumpah. Berapakah isipadu air, dalam ml yang tinggal dalam botol itu ? Soalan 2 1.5l / 1500 ml
  • 23. <ul><li>Ah Chong has RM25. This is of the price of </li></ul><ul><li>bicyle. How much more money </li></ul><ul><li>does Ah Chong need to buy the bicycle ? </li></ul><ul><li>Ah Chong ada RM25. Wang itu ialah daripada harga sebuahbasikal. Berapa banyak wang lagi diperlukan oleh Ah Chong untuk membeli basikal itu ? </li></ul>Soalan 3 A. RM125 B.RM75 C. RM65 D. RM50
  • 24. Penyelasaian 1 : Soalan 3 Konsep pecahan = Denominator mewakili keseluruhan bahagian = 4 bahagian Dia ada RM 25 = RM25 RM25 RM25 RM25 Ada Diperlukan lagi Wang diperlukan = 25 +25+25 = RM75
  • 25. Penyelesaian 2 : Soalan 3 RM25 3 X RM25 = RM75 BAKI DI PERLUKAN LAGI = RM75 ASAL GUNA BAKI PECAHAN NILAI
  • 26. Terima kasih Disediakan oleh : Rosmaizan bt.Othman D20102043751

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