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Definition of oxidation
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Definition of oxidation

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  • 3 things I like:
    - good use of mnemonics
    - SUPER LOVE CHIP AND DALE!
    - Thanks for the video!

    2 things that can be improved:
    - Explore oxidation and reduction in terms of hydrogen and electron gain/loss
    - On slide 8, would be good to superscript the charges so it is clearer for the reader

    1 question:
    - Mannnnnny questions. Try my quiz!

    Good job at verifying your facts!
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  • 3 things i like:detailed information,lots of pictures and enough words.2 to improve more pic and more explanation.I question none-kian leong
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  • 3 things i like:

    a lot of pictures

    different fonts

    LEOGER

    2 areas to be improved on:

    more pictures relavant to the topic

    brighter background

    1 question:

    the LEOGER is found on the internet or by yourselves? Jeremy
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  • 3 things i like - there video theres is little words in a slide there is vivd infomation 2 things to be improve-vary background,more pictures?

    1 question none 7-8/10 edwin
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  • Useful pictures, interesting texts, funny at times. excessive use of pictures and can get pretty stale. where did you get this info from? no errors. -Syakiran Group B
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Transcript

  • 1. Oxidation is gain of
  • 2. Definition of Reduction
  • 3. ExAmPle
  • 4. Hard tO Remember? LEOLose Electrons in OxidationGain Electrons in Reduction
  • 5. VIDEO!!http://www.youtube.com/watch?v=dxlWtsFinT M
  • 6. FUN F@CTS!-My name is BOND…Convalent Bond!:D-When an atom or molecule combines with oxygen, it tends to give up electrons to the oxygen in forming a chemical bond.
  • 7. Pls click to the next pg, thank you
  • 8. For example, in the reaction (unbalanced),MnO4- + H+ -> Mn2+ + H2Othe oxidation of Mn goes from +7 to +2. Thus, Mnis reduced. In the following reaction (unbalanced),H2C2O4 + O2 -> CO2 + H2O C is oxidized, because its oxidation statethe elementchanges from +3 to +4 in the reaction.
  • 9. The oxidation state of an uncombinedelement is .Thatsobviously so, because it hasnt beeneither oxidised or reduced yet! The sum of the oxidation states of all the atoms or ions in a neutral compound is zero.
  • 10. • First determine what the oxidation numbers of your known atoms are.• we know the oxidation number for H is +1.• Then set this value equal to the overall net charge of the ion.• In this case, it is +1.• Our equation now looks like this: 1(4) = 1, You use the multiplier of 4 to indicate that the ammonium ion has 4 hydrogen.• Next substitute a variable in the equation for the missing oxidation number:• +1(4) + N = +1• Solve for N.• +1(4) + N = +1• N + 4 = +1• N = +1 - 4• N = -3• Thus, the oxidation number for Nitrogen is -3.
  • 11. CREDITS:

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