6 1 surf_area_vol_cylinders
Upcoming SlideShare
Loading in...5
×
 

Like this? Share it with your network

Share

6 1 surf_area_vol_cylinders

on

  • 1,649 views

 

Statistics

Views

Total Views
1,649
Views on SlideShare
630
Embed Views
1,019

Actions

Likes
3
Downloads
19
Comments
3

7 Embeds 1,019

http://deepyudha.blogspot.com 1000
http://www.deepyudha.blogspot.com 6
http://deepyudha.blogspot.nl 5
http://deepyudha.blogspot.com.es 4
http://deepyudha.blogspot.jp 2
http://deepyudha.blogspot.ca 1
http://deepyudha.blogspot.in 1
More...

Accessibility

Categories

Upload Details

Uploaded via as Microsoft PowerPoint

Usage Rights

© All Rights Reserved

Report content

Flagged as inappropriate Flag as inappropriate
Flag as inappropriate

Select your reason for flagging this presentation as inappropriate.

Cancel
  • Full Name Full Name Comment goes here.
    Are you sure you want to
    Your message goes here
    Processing…
Post Comment
Edit your comment

6 1 surf_area_vol_cylinders Presentation Transcript

  • 1. 1
  • 2. By MGMP Matematika SMPN 2 Sindang Indramayu
  • 3. SOLIDS / bangun Ruang Standards 8, 10, 11 PYRAMID / Limas PRISM / PrismaCYLINDER / Tabung CONE kerucut SPHERE / Bola 3 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
  • 4. 4
  • 5. base STUDENT’S WORKSHEET SURFACE AREA OF CYLINDER r h h r base Fill in the blank ! r1. Net of cylinder (jaring jaring tabung ) : ....................and ................2. What’ shape (bentuk) Blanket (selimut) of cylinder ........................................?3. The weight (lebar) of rectangle =..........................Cylinder (tabung)4. The length (panjang ) of rectangle =...........................Of Circle ( lingkaran)5. The formula of blanket (selimut) =.................................6. The formula base of Cylinder =............... 57. The formula of surface area of Cylinder =....................................................
  • 6. Let’s cek your answer 6
  • 7. SURFACE AREA OF CYLINDERS base r r2 h 2 rh h r 2 r r2 base rLateral/blanket (selimut) Area: 2 rh Total Surface Area = Lateral Area + 2(Base Area) T= 2 r h + 2 r 2 h= height r= radius 7
  • 8. Standards 8, 10, 11 VOLUME OF CYLINDERS B= r2 V = Bh V= r2 h h rCYLINDER 8PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
  • 9. Standards 8, 10, 11 Find the lateral area, the surface area and volume of a cylinder with a radius of 20 cm and a height of 10 cm. Total Surface Area = Lateral Area + 2(Base Area) T= 2 rh + 2 r2 2 10 cm T=2 ( 20 cm)( 10 cm ) +2 ( 20 cm ) 20 T= 400 2 2 cm + 2(400 cm ) cm T = 400 cm 2 + 800 Cm2 cm 2Lateral Area: T = 1200L =2 rh Volume:L=2 (20 cm )( 10 cm )L=400 cm2 V= r2 h 2 V= ( 20 cm ) ( 10 cm ) 2 V= (400 cm )(10 cm) 3 V= 4000 cm 9 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
  • 10. Standards 8, 10, 11Find the lateral area and the surface area of a cylinder with a circumferenceof 14 cm. and a height of 5cm. Finding the radius: Lateral Area: L =2 rh C=2 r L=2 (7 cm )(5 cm ) r= C 2 L= 70 cm2 Total Surface Area = Lateral Area + 2(Base Area) 14 T= 2 rh + 2 r2 r= 2 2 T = 2 ( 7 cm )( 5 cm ) + 2 ( 7 cm ) r=7 cm T= 70 cm2 + 2(49 cm 2 ) T = 70 cm 2 + 98 cm 2 5 cm T = 168 cm 2 7 cm 10 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
  • 11. Standards 8, 10, 11 Find the Volume for the cylinder below: h 2 4 5First we find the height: Volume: h 2 2 V= r2 h 5 = 4 + h2 2 V= ( 2) (3 ) 25 = 16 + h2 -16 -16 V= ( 4 )(3) 4 5 h=9 2 V= 12 unit3 2 h= 9 h=3 11 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
  • 12. Standards 8, 10, 11 2 The surface area of a right cylinder is 400 cm. If the height is 12 cm., find the radius of the base. We substitute values:Total Surface Area: Subtituting: -( 75.4 ) + _ ( 75.4 )2 - 4(6.28 )(-400)T= 2 r h + 2 r 2 2 400 = 2(3.14)r(12) + 2(3.14)r2 r=T= 400 cm 2( 6.28 )h= 12 cm 400 = 75.4 r + 6.28r 2 -400 -400 -75.4 + _ 5685.16 + 10048 =3.14 r= 12.56 0 = 6.28r 2 + 75.4 r - 400 _ +Using the Quadratic Formula: r = -75.4 15733.2 12.56 _ + 2 r = -75.4 125.43 -b + _ b - 4ac 12.56 X= + - 2a -75.4+125.43 -75.4 -125.43 2 r= r= where: 0 = aX +bX +c 12.56 12.56 50.03 -200.83 r= r= a= 6.28 12.56 12.56 From equation: b= 75.4 r 4 cm r -16 c= -400 12 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
  • 13. Standards 8, 10, 11 SIMILARITY IN SOLIDSAre this two cylinders similar? 4 6 8 3 4 = 8 6 3 These cylinders are NOT SIMILAR 13 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
  • 14. Standards 8, 10, 11 The ratio of the radii of two similar cylinders is 2:5. If the volume of the smaller cylinder is 40 units,3 what is the volume of the larger cylinder. VOLUME 1 < VOLUME 2 Volume: VOLUME 1 VOLUME 2 2 V1 r1 h1 V= r2 h IF 2 2 THEN = V1 = r1 h1 V2 = r2 h 2 V2 r2 h2 2 2 V1 2 r1 h1 V1 r1 h1 r1 h1 = AND = AND IF = = 2 V2 r2 h2 2 V2 r2 h2 They are similar r2 h2 5 Substituting values: 2 40 = 2 2 40 = 4 2 40 8THEN = V2 5 5 V2 25 5 V2 125 (40)(125) = 8V2 What can you conclude about the ratio of 8 8 the volumes and the ratio of the radii? V2 = 625 units 3 14 PRESENTATION CREATED BY SIMON PEREZ. All rights reserved
  • 15. Practice diligently don’t be give up Remember : -Where there is will there is away- You can if you think you can