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# Floatable foundation

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### Floatable foundation

1. 1. Floatable Foundation<br />John Tobias, Brian Jestice, <br />Anthony Cairns, <br />Diane Kohlin<br />
2. 2. What it is?<br />It is a foundation ,that can float, for a dwelling so if the land floods the dwelling will just float instead of being destroyed.<br />
3. 3. Where would they use it?<br />The Republic of South Africa is a country located at the southern tip of Africa, with a 2,798 kilometers (1,739 mi) coastline on the Atlantic and Indian Oceans.<br />
4. 4. 100% Recyclable Materials <br />14 plastic bottles<br />1 palate <br />1 rope <br />
5. 5. Inventor drawings<br />
6. 6. Construction<br />
7. 7. Prototype <br />
8. 8. Testing the Model<br />
9. 9. Calculations<br />Finding an average density of muddy water by comparing the densities of dirt and water in a 1:5 ratio:<br />2002*1/6=333.6667kg/m3<br />1000*5/6=833.3333kg/m3<br />333.7+833.3=1,167kg/m3<br /> density of muddy water: 1167 kg/m3<br />
10. 10. Calculations<br />Finding the amount of water the frame of a whole palate could displace at a maximum.<br />(3)(.50)(5.5)(32)+(2)(1.5)(50.25)(3.5)+(9)(.5)(3.5)(32)=264+527.625+504=1295.625in3<br />1295.625in3= 0.0212 m3<br />
11. 11. Calculations<br />Amount of Water displaced by bottles:<br />14 bottles<br />.002m3 minimum volume of one bottle<br />14(.002m^3)= .028 m3<br />
12. 12. Calculations<br />Finding the total amount of weight the foundation can hold, accounting for only the bottles:<br />∑Forces = 0 = mg<br />ρfluidVdisplacedg<br />mg= ρfluidVdisplacedg<br />mmax= ρfluidVdisplacedg<br />g<br />mmax=ρfluidVdisplaced<br />mmax=(1167kg/m3)(.028m3)= 32.676 kg<br />
13. 13. Calculations<br />Amount of weight the foundation can hold only accounting for the frame:<br />∑Forces = 0 = mg<br />ρfluidVdisplacedg<br />mg= ρfluidVdisplacedg<br />mmax= ρfluidVdisplacedg<br />g<br />mmax=ρfluidVdisplaced<br />mmax=(1167kg/m3)(.0120m3)=14.03kg<br />
14. 14. Calculations<br />Ratio of the frame used to the total size of one palate: 28.5/50.25= 56.72%<br />Therefore the net mass able to be supported by 56% of the palate (current model) is: 14.03kg+32.676kg=46.708kg=102.97 lbs<br />Therefore it can be concluded that a full scale palate is able to support 83.4kg=183.86lbs<br />