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# Floatable foundation

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### Transcript

• 1. Floatable Foundation
John Tobias, Brian Jestice,
Anthony Cairns,
Diane Kohlin
• 2. What it is?
It is a foundation ,that can float, for a dwelling so if the land floods the dwelling will just float instead of being destroyed.
• 3. Where would they use it?
The Republic of South Africa is a country located at the southern tip of Africa, with a 2,798 kilometers (1,739 mi) coastline on the Atlantic and Indian Oceans.
• 4. 100% Recyclable Materials
14 plastic bottles
1 palate
1 rope
• 5. Inventor drawings
• 6. Construction
• 7. Prototype
• 8. Testing the Model
• 9. Calculations
Finding an average density of muddy water by comparing the densities of dirt and water in a 1:5 ratio:
2002*1/6=333.6667kg/m3
1000*5/6=833.3333kg/m3
333.7+833.3=1,167kg/m3
density of muddy water: 1167 kg/m3
• 10. Calculations
Finding the amount of water the frame of a whole palate could displace at a maximum.
(3)(.50)(5.5)(32)+(2)(1.5)(50.25)(3.5)+(9)(.5)(3.5)(32)=264+527.625+504=1295.625in3
1295.625in3= 0.0212 m3
• 11. Calculations
Amount of Water displaced by bottles:
14 bottles
.002m3 minimum volume of one bottle
14(.002m^3)= .028 m3
• 12. Calculations
Finding the total amount of weight the foundation can hold, accounting for only the bottles:
∑Forces = 0 = mg
ρfluidVdisplacedg
mg= ρfluidVdisplacedg
mmax= ρfluidVdisplacedg
g
mmax=ρfluidVdisplaced
mmax=(1167kg/m3)(.028m3)= 32.676 kg
• 13. Calculations
Amount of weight the foundation can hold only accounting for the frame:
∑Forces = 0 = mg
ρfluidVdisplacedg
mg= ρfluidVdisplacedg
mmax= ρfluidVdisplacedg
g
mmax=ρfluidVdisplaced
mmax=(1167kg/m3)(.0120m3)=14.03kg
• 14. Calculations
Ratio of the frame used to the total size of one palate: 28.5/50.25= 56.72%
Therefore the net mass able to be supported by 56% of the palate (current model) is: 14.03kg+32.676kg=46.708kg=102.97 lbs
Therefore it can be concluded that a full scale palate is able to support 83.4kg=183.86lbs
• 15. Bibliography