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International Journal of Research in Computer Science
eISSN 2249-8265 Volume 2 Issue 1 (2011) pp. 7-10
© White Globe Publications
www.ijorcs.org


  SIMULATION OF GENERATION OF HIGH PRESSURE AND
   TEMPERATURE IN METALS UNDER SHOCK LOADING
                                                      Dr. V.P.Singh
                                     Ex Scientist F (Retd), CASSA, MOD, Bangalore
                               Director, Sat Kabir Institute of Technology and Management,
                                       Ladrawan, Bahadurgarh, Haryana (INDIA)

  Abstract: Pressure and Temperature in different            shown that discontinuities in pressure can be removed
metals including radioactive materials behind                at ultra high pressure. In this process, a very strong
converging shock waves, is simulated using                   compression of a condensed medium generates a
generalized form of equation of state. Tait’s equation       colossal internal pressure, even in the absence of
of state of metals, is valid for pressures of the range of   heating due only to the repulsive forces between the
few mega bars and takes into account only elastic            atoms. The material is also very strongly heated by
pressures. At such high pressures, metal undergo             shock waves and, this result in the appearance of a
phase change and normal equation of state no more is         pressure associated with the thermal motion of atoms.
valid. At such pressures, temperature in metals              It is known that thermal energy is not linear function
becomes very high and thermal and excitation                 of temperature and CV also varies with temperature. In
pressures dominate over elastic pressure. It is              the present paper we have taken Einstein Equation for
observed that as shock approaches the center of              thermal energy and have studied the pressure and
sphere, excitation pressure dominates elastic as well        temperature variations behind the converging shock
as thermal pressure.                                         waves. Results of variation of pressure by
                                                             conventional method and by present method are
Keywords: Phase change, shocks in metals and radio-
                                                             compared in table-3.
active materials.
                                                                   II. FORMULATION OF THE PROBLEM
                 I. INTRODUCTION
                                                                It is assumed that a spherical shock wave is moving
   Simulation of high pressure and temperature
                                                             from the surface of a metal (or radioactive material)
generated by imploding shock waves through
                                                             sphere towards its center. Generalized thermal l energy
condensed media, such as metals and radioactive
                                                             of materials given by Einstein Equation of state,
materials, is of great theoretical and practical
importance. Behavior of metals under high pressures                            hν
has been analyzed by many authors [1-4], by taking           ET = 3 N                                                     (1)
into account, the general Hugoniot relationship                         [exp(hν / kT ) − 1]
between shock velocity and particle velocity. This              It is used along with jump conditions [2] to get
linear equation fails when we analyze the material           expressions for pressure and temperature behind
undergoing crystallographic phase change under high
                                                             imploding shock waves. In equation (1) N, h, ν, k are
pressure. Thus, knowledge of the thermodynamic
                                                             Avagadro’s Number, Plank’s constant, natural
properties of the materials is necessary to study their
                                                             frequency of solid material, and Boltzman’s constant
behavior under high pressures and temperatures.
                                                             respectively.
Although, no appreciable [2] difficulties are
encountered in calculating the thermodynamic                 Excitation energy of metals is given by[2,5]
properties of gases, a theoretical description of the                                                                         2/3
                                                                1 ρ                                                  
                                                                          1/ 2
                                                                                                        k 2m
thermodynamic properties of solids and liquids at high       E = β  0          T   2
                                                                                         and β = 21.179      e N 1/ 3  1 
                                                              e 2 o ρ                       o                 e ρ 
pressure generated by very strong shocks, present a                                                     h2           1
very complex problem.                                                                                          (2a)
   Variation of material parameters under shock              where me is the electron mass, and Ne is the number of
loading has been studied by Singh and Renuka [5], by         free electrons per unit volume of the metal.
taking thermodynamic properties of the materials into        Cold energy is given by,
account. In this paper, total energy of system is taken
as sum of cold, excitation and thermal energy. By                 Ec = − ∫ Pc dV                                   (2b)
taking thermal energy as CV T ,with CV constant, it was
Equations for cold, thermal and excitation pressure are,


                                                                                 www.ijorcs.org
8                                                                                                                                          Dr.V.P.Singh

           ρ n                                                                              3 NΓ0 ρ 0 k x 2 (δ − 1)  ρ β T (δ − 5) δ 6 NkΘ 2 ρ 0δ 
                                                                                  g (T , δ ) =                          + 0 0           + 2 x          (8)
Pc = A(S)                     − 1                         (3a)                                     (e − 1)
                                                                                                           x      2
                                                                                                                                          T (e − 1) 2 
           ρ 0 
                                                                                               
                                                                                                                                2                     
                                 
                                                                                      hν
                                                                                  x=      , Γ = Γ0 / δ         (ref [6])
                 E                                                                     kT
                     T
P       = Γ(V)                                                (3b)
    T            V                                                                We get T in terms of δ, from this equation, and then
                                                                                  using equation (4) for P, other parameters can be
     1 Ee                                                                         computed from,
Pe =                                                          (3c)
     2 V
                                                                                                Pδ
                                                                                     U=                                        (9)
where V is specific volume and [5],                                                          ρ1(δ − 1)
                                 2      2
                 2           V (d Pc /dV )
Γ (V) = −                −                                    (3d)                            P(δ − 1)
                 3           2          (dPc /dV)                                    u2 =                                     (10)
                                                                                               ρ1 δ
Using equations(1)-(3), total pressure P and energy E
behind the shock front is obtained,                                                  In the above equations, natural frequency of the
                                                                                  metal is slightly complex parameter. This is computed
                             3 NΓρ 0 δ k Θ             1                          by replacing it by Debye’s temperature given by,
P = A(δ n − 1) +                      Θ/T
                                                   +     ρ 0 β 0δ 1 / 2T 2 (4a)
                                 (e         − 1)       4                          Θ = hν / k
                                                                                                                              (11)
        A  (δ n + n − 1)  3 Nk Θ  1                                             Debye’s temperature values for different type of
E=                        + Θ/T  + β 0δ −1 / 2T 2 (4b)                          metals are given in table -2, and basic parameters are
        ρ 0  δ (n − 1)  (e − 1) 4
                                                                                  given in table-1.

Here        Θ = hν / k , is                  Debye’s        constant        and             III. SOLUTION OF THE PROBLEM
        ρ                                                                            The equations (1) to (4) are solved to get the
δ =        = Shock strength .                      We       observe       from
        ρ0                                                                        pressure, temperature, shock velocity and particle
                                                                                  velocity of the material behind the shock front. These
relations (4) that pressure P is function of density ratio                        parameters are expressed in terms of δ and T. It is not
δ and temperature T. We take δ as the independent                                 possible to solve these equations explicitly in terms of
parameter and express all other paraameters in terms                              one parameter, say δ. Therefore temperature is
of δ. Elliminating U and u from equations (1) of [2],                             expressed in differential form and evaluated by
                                                                                  integrating equation (7) using Runge –Kutta method of
one gets,
                                                                                  fourth order.
(δ − 1)( P + 2 P0 ) = 2 ρ 0δE                                              (5)       In order to express pressure and temperature in
                                                                                  terms of the distance ‘r’ of the shock front from the
where P=P2-P0 and E=E2-E0.
                                                                                  center of the sphere, we use Energy Hypothesis [6].
                                                                                  Transmitted pressure due to the initial compression of
Differentiating this equation with respect to δ, we get,
                                                                                  the metal by the shock transmitted from explosive to
                                                                                  material at its outer boundary is calculated using
                                  dP                    dE
( P + 2 P0 ) + (δ − 1)               = 2 ρ 0 E + 2 ρ 0δ                    (6)    mismatch conditions [6].
                                  dδ                    dδ
                                                                                     Variation of δ as the shock moves from the surface
 Using equations (4) in (5) and after some algebraic                              of metallic sphere to its apex is calculated by using
calculations, we get,                                                             energy hypothesis [6] as,
dT   f (T , δ )                                                                              δ E (δ )
                                                                                             3
   =                                                            (7)                    ro 
dδ   g (T , δ )                                                                         =                                                         (12)
                                                                                      r    δ i E (δ i )
where
                                                                                  where index ‘i’ denotes, values at the explosive-
                   A
                         {
                   ρ δ nδ
                           n +1
                                − (n + 2)δ n + 2 +      }                
                                                                                 material boundary. Energy E ( δ) is given by
f (T , δ ) = − ρ1  2                                                    
                     1

                  T β 0                                                 
                        {δ + 3} − 2 ρ1 E + P2 (T , δ ) / ρ 0 + P0 / ρ 0                              1 2
                  8 δ                                                           E (δ) = E(δ) +         u2
                                                                                                       2                                             (13)


                                                                                                         www.ijorcs.org
Simulation of Generation of High Pressure and Temperature in Metals under Shock Loading                                                                        9

        E (δ )                                                                                VI. ACKNOWLEDGEMENT
where            is given by equation (4b).
                                                               Present work was funded by Defence Research and
Knowing δ as a function of r/r0, other parameters are        Development,, Ministry of Defence.
evaluated from equations (2)-(4).

         IV. RESULTS AND DISCUSSION                                                                      VII. FIGURES USED
  In this paper, we have considered five materials, of
which two are radioactive in nature (Table 1).                                         1.00E+04




                                                                 PxE+10(Kg/ms2)
                                                                                                                                                          Ir
    Variation of pressure for Al, Fe, Stainless Steel                                  1.00E+03
                                                                                                                                                          Mo
(Type 404), Molybdenum (Mo), and Iridium is shown
                                                                                       1.00E+02                                                           SS
in Figure 1, whereas variation of temperature for these
                                                                                                                                                          Fe
metals is given in figures 2. Transmitted pressure in                                  1.00E+01
                                                                                                                                                          Al
Aluminum is low at the metal-explosive interface but
rises fast and becomes infinite at radius equal to 0.3.                                1.00E+00

Similarly pressure in Iron grows faster than Stainless




                                                                                                35

                                                                                                        45

                                                                                                                   55

                                                                                                                           65

                                                                                                                                    75

                                                                                                                                            85

                                                                                                                                                    95
                                                                                             0.

                                                                                                     0.

                                                                                                                0.

                                                                                                                        0.

                                                                                                                                 0.

                                                                                                                                         0.

                                                                                                                                                 0.
steel. In Molybdenum (Mo), pressure rise is slow as
                                                                                                                          Radius
compared to lighter metals, and becomes infinite at
radius ratio 0.1. In figure -3, we have plotted variation
of cold, thermal and elastic pressures in Iron. It is seen   Figure-1: Variation of pressure VS dimensionless radius for
                                                                                 different materials
that in the beginning thermal and elastic pressures are
less than cold pressure but ultimately, thermal pressure
and excitation pressure increase and become more than                                  10000000
elastic pressure. Excitation pressure increases very fast
                                                                   Temperature(oK)



                                                                                                                                                         Ir
and get maximum at radius 0.3 and then starts                                           1000000
                                                                                                                                                         Mo
reducing.                                                                                100000                                                          SS
    It has been observed that as the density of material                                                                                                 Fe
                                                                                          10000
increases, its maximum compression as well as                                                                                                            Al
transmitted pressure from explosive decrease (Table-                                       1000
2).



                                                                                                                                                 00
                                                                                                     3

                                                                                                            4

                                                                                                                   5

                                                                                                                           6
                                                                                                                                   7

                                                                                                                                          8

                                                                                                                                                  9
                                                                                                  0.

                                                                                                         0.

                                                                                                                0.

                                                                                                                        0.
                                                                                                                                0.

                                                                                                                                       0.

                                                                                                                                               0.
                                                                                                                                              1.
                    V. CONCLUSION                                                                                          Radius

    In studying the pressure variation across the shock
                                                             Figure-2: Variation of temperature VS dimensionless radius
using Hugoniot equation of state, it has been observed
                                                                               for different materials
that at high pressures, certain materials show sudden
increase in pressure values or even a discontinuity in
the pressure curve as the shock wave converges from                                        Variations of different Pressures
the surface of the sphere to its center [5]. This is
                                                               PressurexE+07(Kg/ms2)




because this equation does not take into account the                                   1.00E+16
thermal and excitation energy of metals. Figure-3                                      1.00E+14
                                                                                       1.00E+12
gives three pressure components for a typical metal,                                   1.00E+10                                                           Pc
say Iron. It shows that, PT and Pe are of same order                                   1.00E+08                                                           PT
initially, but ultimately Pe becomes much more that PT.                                1.00E+06                                                           Pe
Near the centre, effect of excitation pressure is to                                   1.00E+04
expand where as it is resisted by elastic pressure,                                    1.00E+02
                                                                                       1.00E+00
which creates a uncertainty at such points, resulting in
                                                                                                35

                                                                                                45

                                                                                                55

                                                                                                65

                                                                                                75

                                                                                                85

                                                                                                95
                                                                                                 3




the abnormal behavior of Pe curve. Thermal pressure
                                                                                               0.
                                                                                              0.

                                                                                              0.

                                                                                              0.

                                                                                              0.

                                                                                              0.

                                                                                              0.

                                                                                              0.




first increases and then becomes almost constant and                                                                        Radius
when shock approaches near the centre, again rises.
Figure-1 gives pressure variations, where as figure- 2         Figure 3: Comparison of three components of pressure
gives variation of temperature as shock converges.




                                                                                                         www.ijorcs.org
10                                                                                                              Dr.V.P.Singh


                         A                       Γ at                            β             ρ           E0
         Material                    ΓO                          n
                        Bars                   boundary                      erg/g.deg2      g/cm3      108 erg/g
                      1.8200e
            Al                       2.0          1.35         4.352            500          2.785        16.1
                       +010
                      3.3233e
            SS                      2.17          1.49          4.96            540.6        7.896        12.9
                       +010
                      1.5010e
            Fe                      1.69          1.56          6.68            541              7.85    12.85
                       +010
                      6.8150e
            Mo                      1.520         1.39         3.932            495          10.206       7.2
                       +010
                                              Table 1 Data used in this paper

         Sr.
                      Metal          Debey’s Temperature Θ               δ                  δi           δmax
         No                                   o
                                                K
         1.        Aluminum                   428                      2785               1.25213       1.31154
         2.           Iron                    470                      7850               1.2146        1.2437
         3.      Stainless Steel              470                      7896               1.1689        1.1899
         4.      Molybdenum                   450                      10206              1.09422       1.1035
         5.         Iridium                   420                      10484              1.08848       1.1035
                              Table 2. Comparison table showing pressure values at few points


                  VIII. REFERENCES
[1] H.S.Yadav and V.P.Singh, Pramana, 18, No.4, 331-
    338, April, (1982).
[2] Ya.B.Zeldovich et al.,“Physics of shock waves and high
    temperature hydrodynamic phenomena”, Academic
    Press, New York, (1967).
[3] Ray Kinslow, “High velocity impact phenomena”,
    Academic Press, New York, (1970), R.G.Mcqueen,
    S.P.Marsh, et al.,“The Equation of state of solids from
    shock wave studies”, page no. 294-415.
[4] V.N.Zharkov et. al., “Equations of state for solids at
    high pressures and temperatures”, Consultants Bureau,
    New York, (1971).
[5] V.P.Singh and Renuka DV, Study of phase change in
    materials under high pressure, J. Appl. Physics, 86, no.
    9, 1st Nov 99, pp. 4881-4.
[6] V.P.Singh et al., Proc.Indian Acad.Sci.(Engg.Sci.), 3,
    Pt.2, (1980).




                                                                                      www.ijorcs.org

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Simulation of high pressure and temperature in metals under shock loading

  • 1. International Journal of Research in Computer Science eISSN 2249-8265 Volume 2 Issue 1 (2011) pp. 7-10 © White Globe Publications www.ijorcs.org SIMULATION OF GENERATION OF HIGH PRESSURE AND TEMPERATURE IN METALS UNDER SHOCK LOADING Dr. V.P.Singh Ex Scientist F (Retd), CASSA, MOD, Bangalore Director, Sat Kabir Institute of Technology and Management, Ladrawan, Bahadurgarh, Haryana (INDIA) Abstract: Pressure and Temperature in different shown that discontinuities in pressure can be removed metals including radioactive materials behind at ultra high pressure. In this process, a very strong converging shock waves, is simulated using compression of a condensed medium generates a generalized form of equation of state. Tait’s equation colossal internal pressure, even in the absence of of state of metals, is valid for pressures of the range of heating due only to the repulsive forces between the few mega bars and takes into account only elastic atoms. The material is also very strongly heated by pressures. At such high pressures, metal undergo shock waves and, this result in the appearance of a phase change and normal equation of state no more is pressure associated with the thermal motion of atoms. valid. At such pressures, temperature in metals It is known that thermal energy is not linear function becomes very high and thermal and excitation of temperature and CV also varies with temperature. In pressures dominate over elastic pressure. It is the present paper we have taken Einstein Equation for observed that as shock approaches the center of thermal energy and have studied the pressure and sphere, excitation pressure dominates elastic as well temperature variations behind the converging shock as thermal pressure. waves. Results of variation of pressure by conventional method and by present method are Keywords: Phase change, shocks in metals and radio- compared in table-3. active materials. II. FORMULATION OF THE PROBLEM I. INTRODUCTION It is assumed that a spherical shock wave is moving Simulation of high pressure and temperature from the surface of a metal (or radioactive material) generated by imploding shock waves through sphere towards its center. Generalized thermal l energy condensed media, such as metals and radioactive of materials given by Einstein Equation of state, materials, is of great theoretical and practical importance. Behavior of metals under high pressures hν has been analyzed by many authors [1-4], by taking ET = 3 N (1) into account, the general Hugoniot relationship [exp(hν / kT ) − 1] between shock velocity and particle velocity. This It is used along with jump conditions [2] to get linear equation fails when we analyze the material expressions for pressure and temperature behind undergoing crystallographic phase change under high imploding shock waves. In equation (1) N, h, ν, k are pressure. Thus, knowledge of the thermodynamic Avagadro’s Number, Plank’s constant, natural properties of the materials is necessary to study their frequency of solid material, and Boltzman’s constant behavior under high pressures and temperatures. respectively. Although, no appreciable [2] difficulties are encountered in calculating the thermodynamic Excitation energy of metals is given by[2,5] properties of gases, a theoretical description of the 2/3 1 ρ    1/ 2 k 2m thermodynamic properties of solids and liquids at high E = β  0 T 2 and β = 21.179 e N 1/ 3  1  e 2 o ρ  o e ρ  pressure generated by very strong shocks, present a   h2  1 very complex problem. (2a) Variation of material parameters under shock where me is the electron mass, and Ne is the number of loading has been studied by Singh and Renuka [5], by free electrons per unit volume of the metal. taking thermodynamic properties of the materials into Cold energy is given by, account. In this paper, total energy of system is taken as sum of cold, excitation and thermal energy. By Ec = − ∫ Pc dV (2b) taking thermal energy as CV T ,with CV constant, it was Equations for cold, thermal and excitation pressure are, www.ijorcs.org
  • 2. 8 Dr.V.P.Singh  ρ n   3 NΓ0 ρ 0 k x 2 (δ − 1) ρ β T (δ − 5) δ 6 NkΘ 2 ρ 0δ  g (T , δ ) =  + 0 0 + 2 x  (8) Pc = A(S)   − 1 (3a) (e − 1) x 2 T (e − 1) 2   ρ 0    2      hν x= , Γ = Γ0 / δ (ref [6]) E kT T P = Γ(V) (3b) T V We get T in terms of δ, from this equation, and then using equation (4) for P, other parameters can be 1 Ee computed from, Pe = (3c) 2 V Pδ U= (9) where V is specific volume and [5], ρ1(δ − 1) 2 2 2 V (d Pc /dV ) Γ (V) = − − (3d) P(δ − 1) 3 2 (dPc /dV) u2 = (10) ρ1 δ Using equations(1)-(3), total pressure P and energy E behind the shock front is obtained, In the above equations, natural frequency of the metal is slightly complex parameter. This is computed 3 NΓρ 0 δ k Θ 1 by replacing it by Debye’s temperature given by, P = A(δ n − 1) + Θ/T + ρ 0 β 0δ 1 / 2T 2 (4a) (e − 1) 4 Θ = hν / k (11) A  (δ n + n − 1)  3 Nk Θ 1 Debye’s temperature values for different type of E=   + Θ/T + β 0δ −1 / 2T 2 (4b) metals are given in table -2, and basic parameters are ρ 0  δ (n − 1)  (e − 1) 4 given in table-1. Here Θ = hν / k , is Debye’s constant and III. SOLUTION OF THE PROBLEM ρ The equations (1) to (4) are solved to get the δ = = Shock strength . We observe from ρ0 pressure, temperature, shock velocity and particle velocity of the material behind the shock front. These relations (4) that pressure P is function of density ratio parameters are expressed in terms of δ and T. It is not δ and temperature T. We take δ as the independent possible to solve these equations explicitly in terms of parameter and express all other paraameters in terms one parameter, say δ. Therefore temperature is of δ. Elliminating U and u from equations (1) of [2], expressed in differential form and evaluated by integrating equation (7) using Runge –Kutta method of one gets, fourth order. (δ − 1)( P + 2 P0 ) = 2 ρ 0δE (5) In order to express pressure and temperature in terms of the distance ‘r’ of the shock front from the where P=P2-P0 and E=E2-E0. center of the sphere, we use Energy Hypothesis [6]. Transmitted pressure due to the initial compression of Differentiating this equation with respect to δ, we get, the metal by the shock transmitted from explosive to material at its outer boundary is calculated using dP dE ( P + 2 P0 ) + (δ − 1) = 2 ρ 0 E + 2 ρ 0δ (6) mismatch conditions [6]. dδ dδ Variation of δ as the shock moves from the surface Using equations (4) in (5) and after some algebraic of metallic sphere to its apex is calculated by using calculations, we get, energy hypothesis [6] as, dT f (T , δ ) δ E (δ ) 3 = (7)  ro  dδ g (T , δ )   = (12) r  δ i E (δ i ) where where index ‘i’ denotes, values at the explosive-  A {  ρ δ nδ n +1 − (n + 2)δ n + 2 + }   material boundary. Energy E ( δ) is given by f (T , δ ) = − ρ1  2  1 T β 0   {δ + 3} − 2 ρ1 E + P2 (T , δ ) / ρ 0 + P0 / ρ 0  1 2 8 δ  E (δ) = E(δ) + u2 2 (13) www.ijorcs.org
  • 3. Simulation of Generation of High Pressure and Temperature in Metals under Shock Loading 9 E (δ ) VI. ACKNOWLEDGEMENT where is given by equation (4b). Present work was funded by Defence Research and Knowing δ as a function of r/r0, other parameters are Development,, Ministry of Defence. evaluated from equations (2)-(4). IV. RESULTS AND DISCUSSION VII. FIGURES USED In this paper, we have considered five materials, of which two are radioactive in nature (Table 1). 1.00E+04 PxE+10(Kg/ms2) Ir Variation of pressure for Al, Fe, Stainless Steel 1.00E+03 Mo (Type 404), Molybdenum (Mo), and Iridium is shown 1.00E+02 SS in Figure 1, whereas variation of temperature for these Fe metals is given in figures 2. Transmitted pressure in 1.00E+01 Al Aluminum is low at the metal-explosive interface but rises fast and becomes infinite at radius equal to 0.3. 1.00E+00 Similarly pressure in Iron grows faster than Stainless 35 45 55 65 75 85 95 0. 0. 0. 0. 0. 0. 0. steel. In Molybdenum (Mo), pressure rise is slow as Radius compared to lighter metals, and becomes infinite at radius ratio 0.1. In figure -3, we have plotted variation of cold, thermal and elastic pressures in Iron. It is seen Figure-1: Variation of pressure VS dimensionless radius for different materials that in the beginning thermal and elastic pressures are less than cold pressure but ultimately, thermal pressure and excitation pressure increase and become more than 10000000 elastic pressure. Excitation pressure increases very fast Temperature(oK) Ir and get maximum at radius 0.3 and then starts 1000000 Mo reducing. 100000 SS It has been observed that as the density of material Fe 10000 increases, its maximum compression as well as Al transmitted pressure from explosive decrease (Table- 1000 2). 00 3 4 5 6 7 8 9 0. 0. 0. 0. 0. 0. 0. 1. V. CONCLUSION Radius In studying the pressure variation across the shock Figure-2: Variation of temperature VS dimensionless radius using Hugoniot equation of state, it has been observed for different materials that at high pressures, certain materials show sudden increase in pressure values or even a discontinuity in the pressure curve as the shock wave converges from Variations of different Pressures the surface of the sphere to its center [5]. This is PressurexE+07(Kg/ms2) because this equation does not take into account the 1.00E+16 thermal and excitation energy of metals. Figure-3 1.00E+14 1.00E+12 gives three pressure components for a typical metal, 1.00E+10 Pc say Iron. It shows that, PT and Pe are of same order 1.00E+08 PT initially, but ultimately Pe becomes much more that PT. 1.00E+06 Pe Near the centre, effect of excitation pressure is to 1.00E+04 expand where as it is resisted by elastic pressure, 1.00E+02 1.00E+00 which creates a uncertainty at such points, resulting in 35 45 55 65 75 85 95 3 the abnormal behavior of Pe curve. Thermal pressure 0. 0. 0. 0. 0. 0. 0. 0. first increases and then becomes almost constant and Radius when shock approaches near the centre, again rises. Figure-1 gives pressure variations, where as figure- 2 Figure 3: Comparison of three components of pressure gives variation of temperature as shock converges. www.ijorcs.org
  • 4. 10 Dr.V.P.Singh A Γ at β ρ E0 Material ΓO n Bars boundary erg/g.deg2 g/cm3 108 erg/g 1.8200e Al 2.0 1.35 4.352 500 2.785 16.1 +010 3.3233e SS 2.17 1.49 4.96 540.6 7.896 12.9 +010 1.5010e Fe 1.69 1.56 6.68 541 7.85 12.85 +010 6.8150e Mo 1.520 1.39 3.932 495 10.206 7.2 +010 Table 1 Data used in this paper Sr. Metal Debey’s Temperature Θ δ δi δmax No o K 1. Aluminum 428 2785 1.25213 1.31154 2. Iron 470 7850 1.2146 1.2437 3. Stainless Steel 470 7896 1.1689 1.1899 4. Molybdenum 450 10206 1.09422 1.1035 5. Iridium 420 10484 1.08848 1.1035 Table 2. Comparison table showing pressure values at few points VIII. REFERENCES [1] H.S.Yadav and V.P.Singh, Pramana, 18, No.4, 331- 338, April, (1982). [2] Ya.B.Zeldovich et al.,“Physics of shock waves and high temperature hydrodynamic phenomena”, Academic Press, New York, (1967). [3] Ray Kinslow, “High velocity impact phenomena”, Academic Press, New York, (1970), R.G.Mcqueen, S.P.Marsh, et al.,“The Equation of state of solids from shock wave studies”, page no. 294-415. [4] V.N.Zharkov et. al., “Equations of state for solids at high pressures and temperatures”, Consultants Bureau, New York, (1971). [5] V.P.Singh and Renuka DV, Study of phase change in materials under high pressure, J. Appl. Physics, 86, no. 9, 1st Nov 99, pp. 4881-4. [6] V.P.Singh et al., Proc.Indian Acad.Sci.(Engg.Sci.), 3, Pt.2, (1980). www.ijorcs.org