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# Chapter 4 powerpoint

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### Chapter 4 powerpoint

2. 2. Chapter Four 4-2 Describing Data: Displaying and Exploring DataGOALSWhen you have completed this chapter, you will be able to: ONE Develop and interpret a dot plot.TWODevelop and interpret a stem-and-leaf display.THREECompute and interpret quartiles, deciles, and percentiles. FOUR Construct and interpret box plots. Goals
3. 3. Chapter Four 4-3 Describing Data: Displaying and Exploring DataFIVECompute and understand the coefficient of variation and thecoefficient of skewness.SIXDraw and interpret a scatter diagram.SEVENSet up and interpret a contingency table. Goals
4. 4. 4-4 Stem-and-leaf DisplaysStem-and-leaf Note: an advantagedisplay: A of the stem-and-leafstatistical technique display over afor displaying a set frequencyof data. Each distribution is wenumerical value is do not lose thedivided into two identity of eachparts: the leading observation.digits become thestem and thetrailing digits theleaf. Stem-and-leaf Displays
5. 5. 4-5 Stock prices on twelveconsecutive days for a major publicly traded company 100 90 80 70 60 86, 79, 92, 84, 69, 88, 91 50 1 2 3 4 5 6 7 8 9 10 11 12 83, 96, 78, 82, 85. Example 2
6. 6. 4-6Stem and leaf display of stock prices stem leaf 6 9 7 89 8 234568 9 126 Example 2 (Continued )
7. 7. 4-7Quartiles Divide a set of observations into four equal parts. Quartiles
8. 8. 4-8Quartiles Locate the median, (50th percentile) first quartile (25th percentile) and the 3rd quartile (75th percentile) Quartiles (continued)
9. 9. 4-9Quartiles P Lp = (n+1) 100 where P is the desired percentile Quartiles (continued)
10. 10. 4-10 Using the twelve stock prices, we can find the median, 25th, and 75th percentiles as follows:Quartile 3 L75 = (12 + 1) 75 = 9.75th observation 100 50 Median L50 = (12 + 1) = 6.50th observation 100 25 = 3.25th observationQuartile 1 L25 = (12+1) 100 Example 2 (continued)
11. 11. 4-11 th 12 96 75 percentileQ4 11 92 Price at 9.75 observation = 88 + .75(91-88) 10 91 = 90.25 9 88Q3 8 86 50th percentile: Median 7 85 Price at 6.50 observation = 85 + .5(85-84) 6 84 = 84.50Q2 5 83 4 82 3 79 25th percentileQ1 2 78 Price at 3.25 observation = 79 + .25(82-79) 1 69 = 79.75 Example 2 (continued)
12. 12. 4-12The Interquartile This distance willrange is the distance include the middle 50between the third percent of thequartile Q3 and the observations.first quartile Q1. Interquartile range = Q3 - Q1 Interquartile Range
13. 13. 4-13For a set ofobservations the thirdquartile is 24 and thefirst quartile is 10.What is the quartiledeviation? The interquartile range is 24 - 10 = 14. Fifty percent of the observations will occur between 10 and 24. Example 3
14. 14. 4-14A box plot is a graphical display, based on quartiles, that helps to picture a set of data. Five pieces of data are needed to construct a box plot: the Minimum Value, the First Quartile, the Median, the Third Quartile, and the Maximum Value. Box Plots
15. 15. 4-15 Based on a sample of 20 deliveries, Buddy’s Pizza determined the following information. Theminimum delivery time was 13 minutes and the maximum 30minutes. The first quartile was 15 minutes, the median 18minutes, and the third quartile22 minutes. Develop a box plot for the delivery times. Example 4
16. 16. 4-16Example 4 continued
17. 17. 4-17 Min Q Median Q3 Max 112 14 16 18 20 22 24 26 28 30 32 Example 4 continued
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