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Modelling Workshop Biomechanics 1: Problem
 

Modelling Workshop Biomechanics 1: Problem

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The Modelling Workshop Biomechanics 1 Problem of the Modelling Course of Industrial Design of the TU Delft

The Modelling Workshop Biomechanics 1 Problem of the Modelling Course of Industrial Design of the TU Delft

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    Modelling Workshop Biomechanics 1: Problem Modelling Workshop Biomechanics 1: Problem Document Transcript

    • Workshop H-W-1: The gym Machine Consider a user is using a gym machine: Question A: 1. Build a model to describe the movement of her left leg when the user applies a 35Nm torque on her hip joint.
    • Question B: 2. In another movement, during the movement, the angle θ(t), the angular velocity and the angular acceleration of her left leg (from 1.04 second to 2.0 second) is identified via a motion capture system as the left table. How much torques did she applied on her hip joint in this movement, The table of the measurement data (attention, the restart comman is already included) > restart; with plots : 1.04EC00 1.08EC00 1.86E-01 1.12EC00 1.85E-01 1.16EC00 1.85E-01 1.20EC00 1.91E-01 1.24EC00 2.01E-01 1.28EC00 2.11E-01 1.32EC00 2.43E-01 1.36EC00 2.80E-01 1.40EC00 3.43E-01 1.44EC00 4.16E-01 1.48EC00 > MeasurementTime d 1.86E-01 4.81E-01 1.52EC00 ; MeasurementAngle d 5.75E-01 1.56EC00 6.47E-01 1.60EC00 7.48E-01 1.64EC00 8.15E-01 1.68EC00 8.84E-01 1.72EC00 9.62E-01 1.76EC00 1.02EC00 1.80EC00 1.09EC00 1.84EC00 1.12EC00 1.88EC00 1.20EC00 1.92EC00 1.20EC00 1.96EC00 1.20EC00 2.00EC00 1.19EC00 ;
    • -4.46E-01 -2.76E-01 -2.77E-01 2.36EC00 2.17EC00 1.61EC00 1.72EC00 1.88EC00 1.99EC00 2.03EC00 1.90EC00 2.02EC00 MeasurementAngularVelocity d 2.15EC00 ; MeasurementAngularAcceleration 2.26EC00 2.29EC00 2.19EC00 2.36EC00 2.38EC00 2.51EC00 2.48EC00 2.89EC00 3.02EC00 1.29EC00 -1.41EC00 -5.47E-01
    • 1.87EC00 2.70EC00 2.38EC00 2.19EC00 1.25EC00 1.60EC00 1.91EC00 2.19EC00 2.16EC00 1.69EC00 2.25EC00 3.02EC00 d -3.09EC00 ; -1.67EC00 -8.32E-01 -1.21EC00 -2.18EC00 -1.97EC00 -6.14E-01 -2.08EC00 -7.13E-01 -3.69E-01 -2.41E-01 -7.11E-01 -3.88E-01 1 .. 25 Vectorcolumn MeasurementTime := Data Type: anything Storage: rectangular Order: Fortran_order 1 .. 25 Vectorcolumn MeasurementAngle := Data Type: anything Storage: rectangular Order: Fortran_order
    • 1 .. 25 Vectorcolumn MeasurementAngularVelocity := Data Type: anything Storage: rectangular Order: Fortran_order 1 .. 25 Vectorcolumn MeasurementAngularAcceleration := Data Type: anything Storage: rectangular (1.1.1) Order: Fortran_order We choose: 1. during the movement, all her joints are not moving except the left hip joint; 2. all motion happens in a plane; 3. the length of GL1 is 1.2meter and GL2 is 1.5 meters; 4. the mass M1 of the weight is 5kg; the mass of her is 60 kg, the length of her thigh is 0.4114 m, the length of her shank is 0.4012;, the length of her foot is 0.15 m; 6. to use point mass to approximate the mass moment of inertia; 7. she left leg starts from vertical position; 7. the rope is fixed on her ankle joint; 8. to neglect the radius of the pulley; 9. to use the following mass segment and center of gravity table. Mass segments & center of the mass
    • New maple command: subs - an example > SampleFunction d diff x t , t$2 Cdiff x t , t Cx t d2 d SampleFunction := 2 x t C x t Cx t dt dt > SampleFunction d subs diff x t , t$2 = a, SampleFunction d SampleFunction := a C x t Cx t dt > SampleFunction d subs diff x t , t = v, SampleFunction SampleFunction := a Cv Cx t > SampleFunction d subs x t = x, SampleFunction SampleFunction := a Cv Cx (1.3.1) (1.3.2) (1.3.3) (1.3.4)