Upcoming SlideShare
×

# Alg2 lesson 7-5

120

Published on

0 Likes
Statistics
Notes
• Full Name
Comment goes here.

Are you sure you want to Yes No
• Be the first to comment

• Be the first to like this

Views
Total Views
120
On Slideshare
0
From Embeds
0
Number of Embeds
0
Actions
Shares
0
0
0
Likes
0
Embeds 0
No embeds

No notes for slide

### Transcript of "Alg2 lesson 7-5"

1. 1. Solve each equation, then state the number and typeof roots. one real root two real roots
2. 2. one real root and two imaginary roots
3. 3. two real roots and two imaginary roots
4. 4. Write a polynomial function of least degree withinteger coefficients whose zeros include 2, 1 and -3 x=2 x=1 x = -3 x–2=0 x–1=0 x+3=0 (x – 2)(x – 1)(x + 3) = 0 (x2 – 3x + 2)(x + 3) = 0 x3 + 3x2 – 3x2 – 9x + 2x + 6 = 0 x3 – 7x + 6 = 0
5. 5. Write a polynomial function of least degree withinteger coefficients whose zeros include 4 and 4 – i. Complex x=4 x=4–i x=4+i zeros occur in x–4=0 x–4+i=0 x–4–i=0 conjugate pairs (x – 4) (x – 4 + i) (x – 4 – i)      +1 x2 – 4x – xi – 4x + 16 + 4i + xi – 4i – i2 (x – 4) x2 – 8x + 17
6. 6. Pg. 372
7. 7. State the possible number of positive real zeros, negativereal zeros, and imaginary zeros of 2 sign changes +  + + 2 or 0 positive zeros f(-x) = (-x)3 – (-x)2 + 2(-x) + 4 1 sign change =  x3 – x2 – 2x + 4 1 negative zero    + 2 or 0 imaginary zeros.
8. 8. State the possible number of positive realzeros, negative real zeros, and imaginary zeros of 2 sign changes +  + + + 2 or 0 positive zeros p(-x) = (-x)4 – (-x)3 + (-x)2 + (-x) + 3 2 sign changes = x4 + x3 + x2 - x + 3 2 or 0 negative zeros + + +  + 4, 2, or 0 imaginary zeros.