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Alg2 lesson 6-6
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Alg2 lesson 6-6

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    Alg2 lesson 6-6 Alg2 lesson 6-6 Presentation Transcript

    • Vertex form :
      y = a(x – h)2 + k
      Standard form:
      y = ax2 + bx + c
      -b2a
      -b2a
      Line of symmetry: x = ___
      Vertex: ( ___ , f(____ ))
      Line of symmetry: x = h
      Vertex: (h, k)
      -b2a
      y-intercept = (0, c)
      y-intercept = (0, ah2 + k)
    • y = x2
      Vertex: (0, 0)
    • y = a(x – h)2 + k
      -a  flip upside down
      a>1  skinny
      0<a<1  wide
      +k  shift up
      -k  shift down
      +h  shift left
      -h  shift right
    • y = x2
      Vertex: (0, 0)
      y = x2 + 2
      Vertex: (0, 2)
    • y = x2
      Vertex: (0, 0)
      y = x2 + 2
      Vertex: (0, 2)
      y = x2 - 3
      Vertex: (0, -3)
    • y = x2
      Vertex: (0, 0)
    • y = x2
      Vertex: (0, 0)
      y = (x + 1)2
      Vertex: (-1, 0)
    • y = x2
      Vertex: (0, 0)
      y = (x + 1)2
      Vertex: (-1, 0)
      y = (x – 2)2
      Vertex: (2, 0)
    • y = x2
      Vertex: (0, 0)
      y = (x + 1)2 – 3
      Vertex: (-1, -3)
    • y = x2
      Vertex: (0, 0)
      y = (x – 2)2 + 1
      Vertex: (2, 1)
    • y = x2
      Vertex: (0, 0)
    • Write in vertex form. Then graphthe function.
      complete the square
      Vertex: (-1, 3)
      Example 6-2a
    • Write in vertex form. Then graphthe function.
      Vertex: (-3, -4)
      Example 6-2a
    • Write in vertex form, then graph the function.
      Vertex: (-1, 4)
      Opens down
      skinny
      Example 6-3a
    • Vertex: (1, 2) so and
      Write an equation for the parabola whose vertex is at (1, 2) and passes through (3, 4).
      Example 6-4a