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# Alg2 lesson 2 4

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### Alg2 lesson 2 4

1. 1. Find the slope and y-intercept of the line 6x – 3y = 7<br />
2. 2. slope-intercept equation y=mx+b<br />Write an equation of the line from the graph<br /><ul><li> b = -3
3. 3. m = 4/3</li></ul>3<br />4<br />
4. 4. Let’s start with the slope formula…<br />m<br />
5. 5. Let’s start with the slope formula…<br />
6. 6. Let’s start with the slope formula…<br />
7. 7. Let’s start with the slope formula…<br />
8. 8. Let’s start with the slope formula…<br />
9. 9. Let’s start with the slope formula…<br />Point-Slope form<br />
10. 10. Write an equation of a line containing the point (1,2) with slope of –½ <br />(x1,y1) = (1,2) m = - ½<br />y – y1 = m(x – x1)<br />y – 2 = - ½( x – 1)<br />y – 2 = - ½ x + ½<br /> +2 +2<br />
11. 11. Write an equation of the line containing the points (-2,2) and (3,7)<br />Find the slope: <br />m = 1<br />(x1, y1) = (-2, 2)<br />y – 2 = 1 ( x – (-2))<br />y – 2 = x + 2<br />y = x + 4 <br />(3,7)<br />(-2,2)<br />
12. 12. Write an equation of the line through (6, -5) that is perpendicular to<br />What do we know?<br />We know a point on our line: (6, -5)<br />Do we know the slope of our line?<br />NO<br />Do we know anything about the slope of our line?<br />Our line is perpendicular to <br />So its slope is the opposite reciprocal of ?<br />
13. 13. Write an equation of the line through (6, -5) that is perpendicular to<br />using point-slope:<br />y – (-5) = (x – 6)<br />y + 5 = x + <br />y = x – <br />m = 15<br />m┴ = <br />
14. 14. The “Big 3” forms of linear equations <br />