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Ab initio interview questions and answers |AB Initio Top Interview questions


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ab initio interview questions and answers for freshers and experienced,ab initio interview questions and answers 2013,ab initio intreview questions and answers 2014

ab initio interview questions and answers for freshers and experienced,ab initio interview questions and answers 2013,ab initio intreview questions and answers 2014

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  • 1. Ab Initio Data Warehousing Interview Questions and Answers Question.1 what is the relation between eme, gde and co-operating system? Answer: Eme is said as enterprise metadataenv, gde as graphical development env and co-operating system can be said as abinitio server relation b/w this co-op, eme and gde is as fallowsco operating system is the abinitio server. This co-op is installed on particular o.s platform that is called native o.s .coming to the eme, its just as repository in Informatica, its hold the metadata, transformations, dbconfig files source and targets information’s. Coming to gde its is end user environment where we can develop the graphs (mapping just like in Informatica) designer uses the gde and designs the graphs and save to the eme or sand box it is at user side. Where eme is at server side. Question.2 what is the use of aggregation when we have rollupas we know rollup component in abinitio is used to summarize group of data record. Then where we will use aggregation? Answer: Aggregation and Rollup both can summarize the data but rollup is much more convenient to use. In order to understand how a particular summarization being rollup is much more explanatory compared to aggregate. Rollup can do some other functionality like input and output filtering of records.Aggregate and rollup perform same action, rollup display intermediate result in main memory, Aggregate does not support intermediate result. Question.3 what are kinds of layouts does ab initio supports Answer: Basically there are serial and parallel layouts supported by AbInitio. A graph can have both at the same time. The parallel one depends on the degree of data parallelism. If the multi-file system is 4-way parallel then a component in a graph can run 4 way parallel if the layout is defined such as it's same as the degree of parallelism.
  • 2. Question.4 how can you run a graph infinitely? Answer: To run a graph infinitely, the end script in the graph should call the .ksh file of the graph. Thus if the name of the graph is then in the end script of the graph there should be a call to abc.ksh. Like this the graph will run infinitely. Question.5 how do you add default rules in transformer? Answer: Double click on the transform parameter of parameter tab page of component properties, it will open transform editor. In the transform editor click on the Edit menu and then select Add Default Rules from the dropdown. It will show two options - 1) Match Names 2) Wildcard. Question.6 Do you know what a local lookup is? Answer: If your lookup file is a multifile and partioned/sorted on a particular key then local lookup function can be used ahead of lookup function call. This is local to a particular partition depending on the key. Lookup File consists of data records which can be held in main memory. This makes the transform function to retrieve the records much faster than retrieving from disk. It allows the transform component to process the data records of multiple files fast. Question.7 what is the difference between look-up file and look-up, with a relevant example? Answer: Generally Lookup file represents one or more serial files(Flat files). The amount of data is small enough to be held in the memory. This allows transform functions to retrieve records much more quickly than it could retrieve from Disk. A lookup is a component of abinitio graph where we can store data and retrieve it by using a key parameter.A lookup file is the physical file where the data for the lookup is stored.
  • 3. Question.8 How many components in your most complicated graph? Answer: It depends the type of components you us. Usually avoid using much complicated transform function in a graph. Question.9 Explain what is lookup? Answer: Lookup is basically a specific dataset which is keyed. This can be used to mapping values as per the data present in a particular file (serial/multi file). The dataset can be static as well dynamic ( in case the lookup file is being generated in previous phase and used as lookup file in current phase). Sometimes, hash-joins can be replaced by using reformat and lookup if one of the inputto the join contains less number of records with slim record length.AbInitio has built-in functions to retrieve values using the key for the lookup. Question.10 Have you worked with packages? Answer: Multistage transform components by default use packages. However user can create his own set of functions in a transfer function and can include this in other transfer functions. Question.11 Have you used rollup component? Describe how? Answer: If the user wants to group the records on particular field values then rollup is best way to do that. Rollup is a multi-stage transform function and it contains the following mandatory functions.  initialize  Rollup  finalize Also need to declare one temporary variable if you want to get counts of a particular group.
  • 4. For each of the group, first it does call the initialize function once, followed by rollup function calls for each of the records in the group and finally calls the finalize function once at the end of last rollup call. Question.12 How do you add default rules in transformer? Answer: Add Default Rules — Opens the Add Default Rules dialog. Select one of the following: Match Names — Match names: generates a set of rules that copies input fields to output fields with the same name. Use Wildcard (.*) Rule — Generates one rule that copies input fields to output fields with the same name. 1) If it is not already displayed, display the Transform Editor Grid. 2) Click the Business Rules tab if it is not already displayed. 3) Select Edit > Add Default Rules. In case of reformat if the destination field names are same or subset of the source fields then no need to write anything in the reformat xfr unless you dont want to use any real transform other than reducing the set of fields or split the flow into a number of flows to achieve the functionality. Question.13 what is the difference between partitioning with key and round robin? Answer: Partition by Key or hash partition ->This is a partitioning technique which is used to partition data when the keys are diverse. If the key is present in large volume then there can large data skew? But this method is used more often for parallel data processing. Round robin partition is another partitioning technique to uniformly distribute the data on each of the destination data partitions. The skew is zero in this case when no of records is divisible by number of partitions. A real life example is how a pack of 52 cards is distributed among 4 players in a round-robin manner.
  • 5. Question.14 how do you improve the performance of a graph? Answer: There are many ways the performance of the graph can be improved. 1) Use a limited number of components in a particular phase 2) Use optimum value of max core values for sort and join components 3) Minimize the number of sort components 4) Minimize sorted join component and if possible replace them by in-memory join/hash join 5) Use only required fields in the sort, reformat, join components 6) Use phasing/flow buffers in case of merge, sorted joins 7) If the two inputs are huge then use sorted join, otherwise use hash join with proper driving port 8) For large dataset don't use broadcast as partitioner 9) Minimize the use of regular expression functions like re_index in the transfer functions 10) Avoid repartitioning of data unnecessarily Try to run the graph as long as possible in MFS. For these input files should be partitioned and if possible output file should also be partitioned. Question.15 how do you truncate a table? Answer: From Abinitio run sql component using the DDL "truncate table by using the truncate table component in Ab Initio
  • 6. Question.16 Have you ever encountered an error called "depth not equal"? Answer: When two components are linked together if their layout does not match then this problem can occur during the compilation of the graph. A solution to this problem would be to use a partitioning component in between if there was change in layout. Question.17 what is the function you would use to transfer a string into a decimal? Answer: In this case no specific function is required if the size of the string and decimal is same. Just use decimal cast with the size in the transform function and will suffice. For example, if the source field is defined as string(8) and the destination as decimal(8) then (say the field name is field1). out.field :: (decimal(8)) in.field If the destination field size is lesser than the input then use of string_substring function can be used like the following. Say destination field is decimal (5). Outfield: (decimal(5))string_lrtrim(string_substring(in.field,1,5)) /* string_lrtrim used to trim leading and trailing spaces */ Question.18 what are primary keys and foreign keys? Answer: In RDBMS the relationship between the two tables is represented as Primary key and foreign key relationship. Whereas the primary key table is the parent table and foreign key table is the child table. The criteria for both the tables are there should be a matching column. What is the difference between clustered and non-clustered indices? ...and why do you use a clustered index? Question.19 what is an outer join? Answer: An outer join is used when one wants to select all the records from a port - whether it has satisfied the join criteria or not.
  • 7. Contact For More Information about AB INITIO Online Training #402, 4th Floor, KOUSHIK SAI RESIDENCY, Srinivasa Nagar Colony(East), Ameerpet, Hyderabad, Telangana, INDIA. PIN-500038. Phone: +91 4064600330 Mobile: +91 8008114040 USA: +1 732 325 1626 E-mail: Visit :