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    Tcs 2011with solutions Tcs 2011with solutions Presentation Transcript

    • TCS SAMPLE QUESTIONS For student’s preparation(New Test Pattern 2010 onwards)
    • TCS pattern since year 2010 haschanged. From this year onwards the newpattern has been followed .In the newpattern 35 questions have to be answeredin 60 minutes time. However thesignificant difference is that the Englishpart (verbal, synonyms) has been deletedin the new test pattern; though readingcomprehension is likely to continue – thetest is named “TOUCHSTONE”.
    • Some notable points TCS test is computer based test. Each student will get unique questions – as random questions will pop-up- on computer screen - so do not copy. There will be negative marking – so do not guess. Answer the question only if you are more than 80% sure of the correctness of the answer. You are allowed to use calculators, but not mobile phones. Carry HB pencils, eraser, coloured pencils etc. for answering analytical reasoning questions – rough work.
    • In the new test pattern questions are equally divided amongst the three/ four types as listed below:a) Quantitative Ability about 15 questions.b) Logical Reasoning about 10 questions.c) Analytical Reasoning about 5 questions.d) Reading comprehension about 5 questions.
    • Some sample questions arediscussed in this presentationto facilitate the preparation ofstudents. First let us take thequantitative questions whichcan be typified to some extent.
    • Quantitative 1: Simple TrigonometryQ1) If cosec 18°= sec A, then the measure of A is________a) 18° b) 108°c) 72° d) None of theseAns: c) 72°
    • SOLUTION Cosec 18° = Cosec (90° – 72°) As, Cosec (90 – Ѳ) = Sec Ѳ Cosec (90° – 72°) = Sec 72° Sec 72° = Sec A Hence, A = 72°
    • Quantitative 2 : Problem of AgesQ2) After 2 years, Paul will be 2 times as old as Alice. Presently he is 4 times as old. What is the present age of Paul?a) 1 year b) 4 yearsc) 2 years d) None of theseAns: b) 4 years
    • SOLUTIONLet present age of Paul be x yrs and that of Alice be y yrsAccording to condition no. 1 x + 2 = 2 (y + 2) x – 2y = 4 – 2 x – 2y = 2 -----(i)
    • According to condition no. 2 x = 4ySubstituting x in equation (i) 4y – 2y = 2 2y = 2 Hence, y = 1 years x= 4 years
    • Quantitative 3 : MensurationQ3) A vessel is in the form of a hollow cylinder mounted on a hollow hemisphere. The diameter of the hemisphere is 14 cms and the total height of the vessel is 30 cms . Find the outer surface area of the vessel. (take π = 22/7)a) 1628 cm² b) 1528 cm²c) 1474 cm² d) None of theseAns: c) 1474 cm²
    • SOLUTION d = 14 cm r = 7 cm Height of the cylinder = 30 – 7 = 23 cm Outer Surface Area of the Vessel = curved surface area of hemisphere+ curved surface area of cylinder + πr² (top surface) = 2 πr² + 2πrh + πr² = πr (2π + 2h + r) = 22/7 * 7 ( 2*7 +2*23 + 7) = 22 (14 + 46 + 7) = 22 * 67 = 1474 cm²
    • Quantitative 4 : Linear EquationQ4) A telephone company charges 80 paisa/ min for first 80 min of talk , 70 paisa/ min subsequently up to 130 min and 55 paisa/min beyond 130 min. What would be the amount paid by a subscriber who has used a total of 110 min of talk time?a) Rs. 85 b) Rs. 108.c) Rs. 64 d) None of theseAns: Rs. 85
    • SOLUTION Total Charges = (80 min x 80p) + (30 min x 70p) = 6400p + 2100p = 8500p = Rs. 85
    • Quantitative 5: Linear EquationQ5) (2/3rd) of a number is 4 more than (1/6th) of the same number. What is the number? a) 6 b)8 c)36 d)24Ans: b) 8
    • SOLUTION Let number be x Then 2/3x = 1/6x + 4 2/3x – 1/6x = 4 [(4-1)/6] x = 4 3x/6 = 4 x = 4x6/3 = 8
    • Quantitative 6 : ProbabilityQ6) Paul the octopus who has been forecasting theoutcome of FIFA world cup matches with tremendousaccuracy has now been invited to predict ICC world cupmatches in 2011. We will assume that the world cupcontenders have been divided into 2 groups of 9 teamseach. Each team in a group plays with the other teamsin the group. The top two teams from each group enterthe semi finals ( after which the winner is decided byknockout).However, Paul has a soft spot for India and when Indiaplays with any team, Paul always backs India. Alas, hispredictions on matches involving India are right only 2out of 3 times. In order to qualify for the semi finals, it issufficient for India to win 7 of its group matches. Whatis the probability that India will win the ICC world cup?
    • 6(b)a) (2/3)^10b) (2/3)^9 + 8/3 * (2/3)^9c) 1/3 * (2/3)^9d) (2/3)^10 + 8/3*(2/3)^9Ans: c) 1/3 * (2/3)^9
    • SOLUTION1. To win semifinals India needs to win 7 matches and can loose one.2. To win a match probability = 2/33. Probability of loosing a match = 1/34. To qualify for semifinals India needs to win 7 matches the probability of which is (2/3)⁷5. For India to reach the semifinals the probability is (2/3)⁷ x 1/3.6. Now, to further win semifinals and final both probability is 2/3 X 2/3.7. Therefore overall probability of India wining = (2/3) ⁷ x 1/3 x 2/3 x 2/3 = (2/3)⁹ x 1/3.
    • Note:I. If India wins all the matches i.e. 8+2=10 matches, probability = (2/3)102. The key is that for reaching semi finals India has to win only 7 matches out of 8 and can afford to loose one.
    • Quantitative 7 : ProbabilityQ7) A toy train produces 10 different tunes when it moves around a circular toy track of radius 5 meters at 10 meters per minute. However , the toy train is defective and it now produces only two different tunes at random. What are the odds that the toy train produces 4 consecutive music tunes of the same type?a) 1 in 16 b) 1 in 4c) 1 in 8 d) None of these
    • 7(b)Ans: a) 1 in 16
    • SOLUTION• A toy train produces 10 different tunes in the normal course• But now as the toy train has become defective, it produces only 2 different tunes; so the probability of producing any one tune is ½.• Probability of producing 4 consecutives same tunes = ½ x ½ x ½ x ½ = 1/16 or 1 in 16
    • Quantitative 8 : ProbabilityQ8) Six friends decide to share a big cake. Since all of them like the cake, they begin quarreling who gets to cut the cake first and have a piece of the cake. One friend suggests that they can make a blindfold friend choose from well shuffled set of cards numbered one to six. You check and find that this method works as it should simulating a fair throw of a die. You check by performing multiple simultaneous trials of picking the cards blindfold and throwing a die. You note that the number shown by the method of picking up a card and throwing a real world die, sums to a number between 2 and 12. Which total would be likely to appear more often – 8,9 or 10?
    • 8(b) a) 8 b) 10 c) 9 d) All are equally likelyAns: a) 8
    • SOLUTIONSum making up to number 8 in one set of throw of die and picking up the card, probable sets are = (2,6), (6,2), (4,4), (5,3), (3,5) = Total 5 setsSums making up to number 9, probable sets are = (4,5), (5,4), (6,3), (3,6) = Total 4 setsSums making up to number 10, probable sets are = (5,5), (6,4), (4,6) = Total 3 setsSo probability of 8 would be the maximum appearing more often than others
    • Quantitative 9 : ProbabilityQ9) A lady has fine gloves and hats in hercloset- 18 blue- 32 red and 25 yellow gloves arethere. The lights are out and it is totally dark .Inspite of the darkness she can make out thedifference between a hat and a glove. Shetakes out an item out of the closet only if she issure that it is a glove. How many gloves mustshe take out to make sure that she has a pair of each colour?a) 50 b) 8c) 59 d) 42
    • 9(b)Ans: c) 59
    • SOLUTIONWe have to consider the worst case scenario for being sure.Suppose 1st she takes out all 32 Red gloves (the maximum number possible for one colour)Then all yellow gloves which are 25 in numberAnd then next 2 gloves she takes out that will definitely be of blue colorIn this way to make sure that she has a pair of each color, she has to take out = 32 + 25 + 2 = 59 gloves.
    • Quantitative 10 : ProbabilityQ10) There are 7 children in a family and the youngest child is a boy. What is the probability that all of them are boys ? a) 1/2! b) 1/64 c) 1/128 d) 1/8Ans: b) 1/64
    • SOLUTION :The probability of a child being boy or girl is ½ (assuming it is random)The probability that all children in the family are boys when the youngest child is a boy = ½ x ½ x ½ x ½ x ½ x ½ x 1 = (1/2)^6 = 1/64
    • Quantitative 11 : Number SystemQ11) A number when divided by D leaves a remainder of 3 and when divided by 3D leaves a remainder of 21 . What is the remainder, when twice the number is divided by 3D?a) 15 b) 42c) 3 d) cannot be determinedAns: a) 15
    • • SOLUTION-1. As the remainder is 21 when divided by 3D Therefore, 3 D >21 or D>72. Let us take the next higher value i.e. D=8 & 3D = 24 (a). The first option is number 45 (=24+21) Divided by 24 it leaves a remainder of 21 Divided by 8 it leaves a remainder of 5 So it does not fulfill the conditions (b). Let us try the next possibility i.e. 45+24 = 69 Divided by 24 (3D) it leaves 21 as remainder But divided by D = 8, it leaves 7 as the remainder – so it does not fulfill the condition
    • 3. Let us make next trial with ‘D=9’ 3D = 27 (a). Let first number be 48 Divided by 3D = 27 it leaves 21 as remainder Divided by D=9 it leaves 3 as remainder So 9 is the desired number ‘D’ Let us now divide double the number i.e. 96 by 3D = 27 remainder is 15 So a= 15 is the correct answer
    • Quantitative 12 : Permutation and CombinationQ12) Alok is attending a workshop “How to do more with less” and todays theme is Working with fewer digits. The speakers discuss how a lot of miraculous mathematics can be achieved if mankind (as well as womankind) had only worked with fewer digits. The problem posed at the end of the workshop is How many four digit numbers can be formed using the digits 1, 2,3,4 ,5 ( but with repetition) that are divisible by 4? Can you help Alok find the answer?
    • 12 (B) a)100 b) 125 c) 75 d) 85Ans: b) 125
    • SOLUTIONA number to be divisible by 4 the last 2 digits should be divisible by 4To fill the last two digits that are divisible by 4 are (1,2), (2,4), (3,2), (4,4), (5,2)Therefore there are 5 possibilities.And the rest 2 digits can be filled in ⁵P₅ ways.So total there are 5*5*5 ways = 125 ways
    • Quantitative 13 : Permutation and CombinationQ13) A research lab in Chennai requires 100 mice and 75 sterilized cages for a certain set of laboratory experiments. To identify the mice, the lab has prepared labels with numbers 1 to 100 , by combining tags numbered 0 to 9. The SPCA requires that the tags be made of toxin-free material and that the temperature of the cages be maintained at 27 degree Celsius. Also , not more than 2 mice can be caged together and each cage must be at least 2 sq. ft in area. The 5 experiments to be conducted by lab are to be thoroughly documented and performed only after a round of approval by authorities. The approval procedure takes around 48 hours. How many times a tag having number 4 is used by the lab in numbering these mice?
    • 13(b) a) 9 b) 19 c) 20 d) 21Ans: b) 19
    • SOLUTION• Tag having number 4‘ are as follows• 4, 14, 24, 34, 44, 54, 64, 74, 84, 94• 40, 41, 42, 43, 45, 46, 47, 48, 49• So a total of 19 times.
    • Quantitative 14 : Permutation and combinationQ14) 20 people meet and shake hands. What is the maximum number of hand shakes possible if there is to be one ‘cycle’ of handshakes { a cycle of handshake is a sequence of people (a1,a2,…..ak) such that people (a1,a2),(a2,a3)…..(a(k-1),ak), (a20,a1) shake hand} a) 18 b) 19 c) 20 d) 21Ans: c) 20
    • SOLUTION 20 1 2 3 19 4 5 18 6 17 16 7 8 15 9 14 10 13 12 11 To make a complete cycle number of handshakes required is 20
    • Quantitative 15 : Time and DistanceQ15) On planet korba, a solar blast has melted the ice caps on its equator. 9 years after the ice melts, tiny planetoids called Echina start growing on the rocks. Echina grows in the form of a circle ,and the relationship between the diameter of this circle and the age of echina is given by the formula d = 4*√ (t-9) for t ≥ 9 where d represents the diameter in mm and t the number of years since the solar blast. Jagan recorded the radius of some echina at a particular spot as 7mm. How many years back did the solar blast occur?
    • 15(b) a) 17 b) 21.25 c) 12.25 d) 12.06Ans: b) 21.25
    • SOLUTIONThe relationship between the diameters of the circle and the age of Echina is given by the formulaD = 4 x √(t – 9) for t>=9If radius r is 7 mm then diameter = 7 x 2 = 14 mm 14 = 4 x √(t – 9) 14/4 = √(t – 9) 7/2 = √(t – 9) squaring both sides 49/4 = (t – 9) So t = 21.25
    • Quantitative 16 : Time and DistanceQ16) Ferrari S.P.A is an Italian sports carmanufacturer based in Maranello, Italy. Founded byEnzo Ferrari in 1928 as Scuderia Ferrari , thecompany sponsored drivers and manufactured racecars before moving into production of street-legalvehicles in 1947 as Ferrari S.P.A. Throughout itshistory, the company has been noted for itscontinued participation in racing, especially inFormula One where it has enjoyed great success .Rohit once bought a Ferrari . It could go 4 times asfast as Mohans old Mercedes. If the speed ofMohans Mercedes is 46 km/hr and the distancetraveled by the Ferrari is 953 km, find the total timetaken for Rohit to drive that distance.
    • 16(b) a) 20.72 hr b) 5.18 hr c) 238.25 hr d) 6.18 hrAns: b) 5.18 hr
    • SOLUTIONSpeed of Mohans Mercedes = 46 km/hrSpeed of Rohit’s Ferrari = 4 times of Mohans Mercedes = 4 * 46 km/hr = 184 km / hrDistance = 953 kmTime taken by Rohit’s Ferrari = Distance / Speed = 953 km/ 184 km/hr = 5.18 hrsThe total time taken for Rohit to drive that distance will be 5.18 hrs
    • Quantitative 17 : Pipes and Cisterns Q17) There are two water tanks A and B, A is much smaller than B. While water fills at the rate of one litre every hour in A, it gets filled up like 10, 20, 40, 80, 160... Litres per hour in tank B.( At the end of first hour, B gets 10 litres , second hour it gets 20 litres more, and so on). If tank B is 1/33 filled after 5 hours, what is the time still required (in hours) to fill it completely? a) 26 hrs b) 25 hrs c) 5 hrs d) 27 hrsAns: c) 5 hrs
    • SOLUTIONThe data has been shown in the form of a table Hours Water filled in B Cumulative Water filled in that hr (in lts) in B (in lts) 1 10 10 2 20 30 3 40 70 4 80 150 5 160 310
    • After 5 hrs the tank is 1/33 filled which is 310 litersSo applying unitary methodWhen 1/33 is equal to 310 ltsTherefore, the total capacity of tank B will be = 310 lts * 33 = 10230 lts
    • Let us construct the chart further Hours Water filled in B Cumulative Water filled in that hr (in lts) in B (in lts) 1 10 10 2 20 30 3 40 70 4 80 150 5 160 310 6 320 630 7 640 1270 8 1270 2550 9 2560 5110 10 5120 10230Therefore, after 5 more hours the tank B will be completely filled
    • Quantitative 18 : Ratio and ProportionQ18) A researcher at Sony Computer Sciencelaboratories is also a jazz musician. He decided tobuild a robot able to improvise like a pro. Named“Continuator”, the robot can duet with a livemusician in real- time. It listens to a musical phraseand then computes a complementary phrase withthe same playing style. If the cost of making therobot is divided between materials , labour andoverheads in the ratio of 4:6:2 and if the materialscost $108. What is the cost of the robot?
    • 18(b) a) $270 b) $324 c) $216 d) $ 648Ans: b) $ 324
    • SOLUTIONRatio = 4:6:2Let x be the total costSince, the cost of material = 108$Which was equal to4/(4+6+2) * x = 108 $Therefore, x = 324 $
    • Quantitative 19 : Ratio and Proportion with Linear EquationsQ19) In the year 2002, Britain was reported to have had 4.3million closed – circuit television (CCTV) cameras – one for every 14 people in the country . This scrutiny is supposed to deter and detect crime. In one criminal case, the police interrogates two suspects . The ratio between the ages of the two suspects is 6:5 and the sum of their ages is 55 years. After how many years will the ratio be 8:7.?
    • 19(b)a) 11 b) 6c) 10 d) 5Ans: c) 10
    • SOLUTIONSince, the ratio of ages is 6:5Therefore, ages can be 6x and 5x6x+5x= 55 yearsx= 5The two ages will be 30 years and 25 yearsNew ratio = 8:7No. of years required = 30+y = 8 25 +y 7On solving y = 10 yearsAfter 10 years the ratio between their ages will be 8:7.
    • Quantitative 20 : Average speed Q20) A man jogs at 6 mph over a certain journey and walks back the same route at 4 mph. What is his average speed for the journey? a) 4 mph b) 5 mph c) 2.4 mph d) 4.8 mphAns: d) 4.8 mph
    • SOLUTION• Average speed = 2xy or (Total Distance) x+y Total Timex = 6 mphy= 4 mph• Average speed = 2*6*4 6+4 = 4.8 mph
    • Quantitative 21 : SimplificationQ21) Spores of a fungus, called late blight, grow andspread infection rapidly. These pathogens wereresponsible for the Irish potato famine of the mid-19th century. These seem to have attacked thetomato crops in England this year. The tomato cropshave reduced and the price of the crop has risen up .The price has already gone up to $45 a box from $27a box a month ago. How much more would avegetable vendor need to pay to buy 27 boxes thismonth over what he would have paid last month?
    • 21(b) a) $27 b) $ 18 c) $45 d) $ 486Ans: d) $ 486
    • SOLUTION• Difference in two prices = $ 45 - $ 27 = $ 18Amount that the vendor needs to pay to buy 27 boxes this month over what he would have paid last month = $ 18 * 27 = $ 486
    • Quantitative 22 : SimplificationQ22) (40*40*40 – 31*31*31) = ? (40*40+40*31+31*31) a) 8 b) 9 c) 71 d) 51Ans: b) 9
    • SOLUTION• Let x be 40 and y be 31(40*40*40 – 31*31*31) / (40*40+40*31+31*31)Is in the form of x3 - y 3 x2 + xy + y2 = (x2 + xy + y2 ) ( x – y) x2 + xy + y2 = ( x – y) = 40 – 31 = 9
    • Quantitative 23 : CubesQ23) Susan made a block with small cubes of 8 cubic cm volume to make a block 3 small cubes long, 9 small cubes wide and 5 small cubes deep. She realizes that she has used more small cubes than she really needed. She realized that she could have glued a fewer number of cubes together to look like a block with same dimensions, if it were made hollow. What is the minimum number of cubes that she needs to make the block?
    • 23(b) a) 114 b) 135 c) 21 d) 71Ans: a) 114
    • 3SOLUTION 9 1 7 3 5 Total number of cubes used = 3 * 9 * 5 = 135 Number of cubes required to make a hollow cube = (3*9*5)- (1*7*3) = 135 -21 = 114
    • Note: Only two outer cubes on either end facewill make the faces, so inner blocks can beremoved to make a hollow or 1*7*3= (3-2)(9-2)(5-2) blocks can be removed from inside tomake it hollow.
    • Quantitative 24 : Co-ordinate GeometryQ24) Determine the distance between x- intercept and z-intercept of the plane where equation is 6x+8y-3z=72. a)3 b)26.83 c)9 d)25.63Ans: b) 26.83
    • SOLUTION• 6x+8y-3z=72 x + y - z = 172/6 72/8 72/3X- intercept = (72/6, 0, 0) = (12, 0, 0)Y- intercept = (0, 0, -72/3) = (0, 0, -24)Distance between x-intercept and z-intercept of the plane = √[( x1- x2)2 + (y1-y2)2 + (z1-z2)2] =√[( 12- 0)2 + (0-0)2 + (0+24)2] = 26.83Or simplify √(x²+z² )= √(12²+ 24²) = 26.83
    • Quantitative 25 : Co-ordinate GeometryQ25) The vertices of Δ ABC are point A (1,2), B(4,6), C(-4,12). Which of the following is true?a) ABC is not a right angled Δb) It is a right angled Δ with right angle at Cc) It is a right angled Δ with right angle at Bd) It is a right angled Δ with right angle at AAns: c) It is a right angled Δ with right angle at B
    • SOLUTIONSide AB = √ [(4-1)2 + (6-2)2 ] = 5 unitsSide BC = √[ (-4-4)2 + (12-6)2 ] = 10 unitsSide CA = √[ (1+4)2 + (12-2)2 ] = √125 unitsFor a right-angled triangle H2=p2+b2 (√125)2=102 +52CA2 = AB 2+BC2Hence it is right angled at B
    • Quantitative 26 :Time and WorkQ26) A seamstress buys a certain amount of Gingham cloth which comes in rolls that are exactly 56 inches wide. She has also bought a certain length of Seek sucker cloth which is 35 inches wide. The seamstress first focuses on the Gingham roll and discovers that she has 116 yards of Gingham and she wants to divide the gingham into 116 lengths of 1 yard each. She wants to have twice as many pieces of seek sucker as she does of the Gingham. It takes 4 seconds to cut each length of Gingham. Working non-stop, how long (in seconds) will it take her to cut all the 116 pieces?
    • 26(b) a) 464 secs b) 460 secs c) 463 secs d) 465 secsAns: b) 460 secs
    • SOLUTION• It takes 4 seconds to cut each length of Gingham• So to cut 116 pieces, total time required = (116-1) * 4 = 460 sec
    • Quantitative 27 : Arithmetic ProgressionQ27) A long thin strip of width 7 cm is kept on a flat surface. Another identical strip is kept on it in an overlapping manner such that the combined width of the two is 11 cm. What is the width of 55 such strips kept like this?a) 224 b) 223c) 225 d) None of theseAns: b) 223
    • SOLUTION 4 7 4 7 7+4+4+4+……….+4 = 4*54+7 = 223
    • Quantitative 28 : AveragesQ28) Six persons with different ages are standing in a queue. After two years their average age will be 43 years. A seventh person joins them. The current average age has now become 45 years. Find the age of seventh person (in years)?a) 55 years b) 59 yearsc) 69 years d) None of theseAns: c) 69 years
    • SOLUTION• Present average age of group = 43-2 = 41 years• When 7th person joins the average = 45 years• Total age of 7 people = 41*6 + x• Where x is the age of the 7th person joining the group• Average = total/ number of observations• 45 = (246 +x) / 7• On solving• X= 69 years
    • Quantitative 29 : Heights & distance Q29) Two vertical poles of heights 6m and 11m stand on a plane ground. The distance between their feet is 12m. A rope is tied tightly from the top of one pole to the top of the other. Find the length of the rope (round off)? a) 14m b)13m c) 15m d) None of theseAns: b) 13m
    • SOLUTION 5m 11 m 12 m 6m 12 m A 2 + B 2 = H2 144 + 25 = 169 H = 13 m Therefore, Length of rope = 13 m
    • Quantitative 30 : Heights & distance with Trigonometry Q 30) Standing on top of a high building, I measure an angle of elevation of a building 25 metres away as 45 degrees. The angle of depression of the ground level of the same building is also measured as 45 degrees. How tall is that building? a) 10m b) 20m c) 25m d) 50mAns: d) 50m
    • C Solution Since Angle of Elevation = 45o Tan 45 = p / b = BC/OB = 1 45o p/25= 1 25 45o B ---------------------------------- OTherefore, P = 25m Similarly ---- -- 25 ---- - AB = 25m -- ---- - ---- Total Height of the taller --- ---- - - --building = AB + BC = 25m + A --- ---- 25m = 50m 25
    • Logical reasoning-1Q31) One day Alice meets Pal and Byte in fairyland. She knows that Pal lies on Mondays, Tuesdays and Wednesdays and tells the truth on the other days of the week .Byte, on the other hand, lies on Thursdays, Fridays and Saturdays, but tells the truth on the other days of the week. Now they make the following statements to Alice – Pal: “Yesterday was one of those days when I lie”. Byte: “Yesterday was one of those days when I lie too”.What day is it ?
    • 1(b)a) Thursday b) Tuesdayc) Monday d) SundayAns: a) Thursday
    • SOLUTION Mon Tues Wed Thurs Fri Sat SunAlice √ √ √ Pal √ √ √
    • Logical Reasoning-2 Q32) Rearrange the following letters to make a meaningful word and choose from the options given, the category in which it lies. “RAPETEKA” a) Bird b) Vegetable c) City d) FruitAns: ‘PARAKEET’. a) Bird
    • Logical Reasoning-3Q33) In the reading room of a library, there are 23 reading spots. Each reading spot consists of a round table with 9 chairs placed around it. There are some readers such that in each occupied reading spot there are different numbers of readers. If in all there are 36 readers, how many reading spots do not have even a single reader? a) 8 b) 15 c) 16 d) None of theseAns: b) 15 
    • SOLUTION 23 reading spots Each reading spot consists of 9 chairs placed around it so there are some readers such that in each occupied reading spot there are different number of readers. Soon first table 1 person will sit. On second table 2 person will sit If there are 36 readers then 1+2+3+4+5+6+7+8=36 Only 8 tables will be occupied. Therefore, 23-8=15 reading spots will not have even a single reader.
    • Logical reasoning-4Q34) Middle – earth is a fictional land inhabited by Hobbits, Elves, dwarves and men. The Hobbits and the Elves are peaceful creatures who prefer slow, silent lives and appreciate nature and art. The dwarves and the men engage in physical games. The game is as follows . A tournol is one where out of the two teams that play a match, the one that loses get eliminated. The matches are played in different rounds where in every round , half of the teams get eliminated from the tournament. If there are 8 rounds played in a knock-out tournol how many matches were played?
    • 4(b) a) 257 b) 256 c) 72 d) 255Ans: d) 255
    • SOLUTIONRound No. of matches No. of played contestants 8 1 2 7 2 4 6 4 8 5 8 16 4 16 32 3 32 64 2 64 128 1 128 256Total 255
    • Logical Reasoning-5Q35) Consider two tumblers, the first containing Water and second containing coffee. Suppose you take one spoon of water out of the first tumbler and pour it into the second tumbler. After stirring well you take one spoon of the mixture from the second tumbler and pour it back into the first tumbler. Which one of the following statement holds now?
    • 5(b) a) There is less coffee in the first tumbler than water in the second tumbler. b) There is more coffee in the first tumbler than water in the second tumbler. c) There is as much coffee in the first tumbler as there is water in the second tumbler. d) None of the statements holds true.Ans: d) None of the statements holds true.
    • Logical reasoning-6Q36) A taxi driver commenced his journey from a point and he drove 10 km towards north and turned to his left and drove another 20 km. After meeting a friend here, he turned to his right and continued to drive another 10 km. In which direction is he now with respect to the starting point? a)West b)South c)North d)EastAns: c) North
    • SOLUTION North10 KM 20 KM 10 KM
    • Logical reasoning-7 Q37) A school yard contains only bicycles and 4 wheeled wagons. On Tuesday, the total number of wheels in the schoolyard was 114. What would be the possible number of bicycles? a)18 b)17 c)16 d) 8Ans: b) 17
    • SOLUTION Number of wheels in a bicycle = 2 Number of wheels in a wagon = 4 Total number of wheels =114a) 18 If bicycles are 18 then the number of wheels in bicycle = 36 Remaining wheels = 114-36=78 Now this should be divisible by four because the remaining wheels are of wagons 78/4 = 19.5 Solution not feasible.
    • b)17 Number of wheels in bicycle = 17×2=34 Now 114 – 34=80/4 = 20c) 1616×2 = 32 114-32 = 82/4 =20.5d) 88×2 = 16 114-16 =98 = 24.5
    • Logical reasoning-8Q38) A pie is to be divided among 20 people. A man eats 3 pieces, a woman eats 2 pieces and a child eats ½ a piece of pie. There are 20 pieces of pie in all. What is the number of men, women & children, so that 20 people in total and everyone gets pie as per his/her requirement and there is no shortage or excess of pie at the end?
    • 8(b)a) 7 women, 1 man, 12 childrenb) 5 women, 1 man, 14 childrenc) 4 women, 2 men, 12 childrend) None of theseAns: b) 5 women, 1 man, 14 children
    • SOLUTIONNumber of People = 20Pieces eaten by men = 3Pieces eaten by women = 2Pieces eaten by children = ½ Options Women Men Children Total no. of Total no. of Pieces People a 7(7×2=14) 1(1×3=3) 12(12×1/2=6) 23 20 b 5(5×2=10) 1(1×3=3) 14(14×1/2=7) 20 20 c 4(4×2=8) 2(2×3=6) 12(12×1/2=6) 20 18
    • Logical reasoning-9 (Direction)Q39) A scientist was researching on animalbehavior in his lab. He was very interested inanalyzing the behavior of bears. For somereason he traveled 1mile in north direction &reached at North Pole. There he saw a bear. Hethen followed the bear around 1 hr with a speedof 2km/hr in east direction. After that he traveledin south direction & reached at his lab in 2 hrs.Then what is the color of the bear?a) Black b) Brownc) White d) None of these
    • 9(b)Ans: c) White
    • Logical Reasoning-10(Series)Q40) When Lucy was young her father would take his daughter to the terrace and explain about constellations to his daughter and then he leaves her alone in the terrace to find few of them all by herself. Lucy finds around 25 groups of stars that appear to her as constellations. She draws 7 patterns of the constellations in her notebook and notes down the number of stars in each of them. She counts 5 stars in first constellation and 15 in next. She counts a number the third time and forgets to note it down. The next four constellations she counts are 51,53,159,161. Next day her father looks at the notebook and wants to know the number of stars in the third constellation. Lucy only remembers that number of starts counted in each of the constellation followed a pattern 5, 15, x, 51, 53, 159, 161.
    • 10(b)What is the value of x?a) 19 b) 45c) 16 d) 17Ans: d) 17
    • SOLUTION5 15 x 51 53 159 161 ×3 +2 ×3 +2 ×3 +2
    • Analytical reasoning-1 Q41) Bob, Peter, Oliver and 2 girls –Raven and Chelsey are to be seated in a row. Raven often sits to left of Bob. No girl sits at extreme positions and middle positions. Peter always sits at the extreme position. Who sits to the right of Chelsey? a)Oliver b)Bob c)Peter/Oliver d)PeterAns: c)Peter/Oliver
    • SOLUTIONThere are two possible solutions: Peter Chelsey Oliver Raven Bob Peter Raven Bob Chelsey OliverOliver Peter
    • Analytical reasoning-2 Q42) A man is standing in front of a painting of a man, and he tells us the following: “ Brothers and sisters have I none, but this man’s father is my father’s son”. Who is on the painting?a) The man himselfb) The man’s sonc) The man’s fatherd) Can’t be determined
    • 2(b)Ans: b) The man’s son
    • SOLUTION FatherMan’s Father Man
    • Analytical reasoning-3Q43) There are 5 materials to make a perfume: Lilac,Balsalmic, Lemon, Woody and Mimosaic. To make aperfume that is in demand the following conditionsare to be followed: Lilac and Balsalmic go together.Woody and Mimosaic go together but one of anyone group does not go with any other of the othergroup together. Lemon can be added with anymaterial. All of the following combinations arepossible to make a perfume EXCEPT:
    • 3(b)a) Balsalmic and Lilacb) Woody and Lemonc) Mimosaic and Woodyd) Mimosaic and LilacAns: Mimosaic and Lilac.
    • SOLUTIONLILAC ----------------BALSAMICWOODY--------------MIMOSAICLEMON CAN BE ADDED TO ALLLILAC ----------------BALSAMIC x WOODY--------------MIMOSAIC
    • Directions for question 43: Read the passagegiven below and answer the questions thatfollow.
    • Analytical Reasoning-4Q44) In a certain society, there are 2 marriage groups, red and brown. No marriage is permitted within a group. On marriage, males become part of their wife’s group; women remain in their own group. Children belong to the same group as their parents. Widowers and divorced males revert to the group of their birth. Marriage to more than one person at the same time and marriage to a direct descendant are forbidden.
    • 4(b)i) A male born into the brown group may havea) an uncle in either groupb) a brown daughterc) a brown sond) a son-in-law born into the red groupe) a daughter-in-law in the red groupAns: a)
    • MOTHER MOTHER’S FATHERFATHER’S BROTHER FATHER BROTHER MALE
    • 4(c)ii) Which of the following is not permitted under the rules as stated?a) a brown male marrying his father’s sisterb) A red female marrying her mother’s brotherc) a man born red, who is now a widower, marrying his brother’s widowd) a widower marrying his wife’s sisterAns: b)
    • SOLUTION
    • MOTHER FATHERFATHER’S SISTER FATHER MALE
    • MOTHER MOTHER’S BROTHER FEMALE
    • Reading Comprehension-1Q45)The recent news, that local hospitals have had to reroute seriously illpatients because the communitys critical-care beds are full, is worrisome.Earlier this week, four of the six local hospitals ran out of space for thecritically ill and had to turn people away.Federal law requires hospitals to treat anyone who walks in. As a result ofhaving to treat large number of uninsured patients, the emergency roomsoften become an economic drain on their hospitals. Doctors now want to setup their own free-standing ambulatory surgical facilities and diagnosticcenters. Critics contend this would leave hospitals with less revenue and thesame number of indigents to treat. A bill was recently introduced to phaseout the need for a "certificate of public need" for non-hospital-basedfacilities, provided those facilities met stringent regulations andrequirements. This would have made it easier to set up alternative facilitiesto help indigent patients. The finance committee balked at the hefty priceand killed the bill, another casualty of a failed legislative session.Unfortunately, the problem of access to medical care for those of limitedmeans is not going to go away anytime soon and, despite the well-intendedregulations, full hospitals compromise everyones welfare. Healthycompetition with small neighborhood surgical and diagnostic centers may bewhat is necessary to help dampen rising medical costs. But under nocircumstances should the hospitals be forced to care for everybody withouthealth insurance while competitors operate free of the burden of caring forthose unable to pay.
    • 1(b)Which of the following best describes the tone of the passage?a) neutralb) positivec) persuasived) angrye) ReverentialAns : c) persuasive
    • 1(c) Which of the following is cited as a factor which has contributed to the overburdening of hospitals?I Failure to pass legislation which would have mitigated the problemII Limited access to medical care for the poorIII Federal lawa) I onlyb) II onlyc) III onlyd) I and IIe) I, II, and IIIAns : e) I, II, and III
    • 1(d) The author cites the failed legislation in order to show thata) the legislature will never resolve this issue.b) the finance committee does not care about the uninsured citizens.c) there will continue to be uninsured hospital patients for a long time to come.d) the legislature does not have the decision to resolve this issue.e) the doctors successfully lobbied the finance committee.Ans : c) there will continue to be uninsured hospital patients for a long time to come.
    • 1(e) Which of the following is a conclusion supported by the passage?a) If doctors want to run their own facilities, they should be required to take in at least some of the indigents.b) The government should provide health insurance for those unable to buy their own.c) Voters should tell the finance committee members that they will not be reelected if they do not pass some new legislation.d) Emergency rooms that turn patients away due to overcrowding are derelict in their duty .e) The fundamental problem facing hospitals now is that health care costs have risen dramatically in recent yearsAns : a) If doctors want to run their own facilities, they should be required to take in at least some of the indigents.
    • SUMMARYThe pattern of the paper can be summarized as follows:1. In Quantitative ability the following topics are to be covered- Simple trigonometry( sin-cosine, cot- tan, cos-cosec) Problem of ages Heights & distances Mensuration ( rings, spheres etc.) Simple Geometry Co-ordinate Geometry Number System ( simplification, factorization based on (a+b)2, (a+b)3) Arithmetic & Geometric Progression
    • Pipes & CisternsRatio & ProportionAveragesAverage SpeedProfit & LossCubes (volume & surface area)Simple linear equationsTime & WorkTime & DistanceProbability (atleast 3 questions willcome in each paper)Permutation & Combination (atleast 2questions will come in each paper)
    • 2. In logical Reasoning Simple series ( at least one question) Directions Small puzzles3 You may get one or two passages on Analytical Reasoning.4 A passage on Reading Comprehension may appear with 3 or 4 questions.
    • THANK YOU &WISH ALL OF YOU ALL THE BEST