CR-3 Computer Wind Side 2/2
5.FINDING WINDS IN FLIGHT <ul><li>Given: </li></ul><ul><ul><li>TAS 180 mph </li></ul></ul><ul><ul><li>TC  175º </li></ul><...
 
<ul><li>TC – TH = WCA </li></ul><ul><li>175º – 160º =  15º </li></ul><ul><li>WCA is 15º Left. Determine the “effective” TA...
 
<ul><li>ETAS =  174  mph </li></ul><ul><li>ETAS – GS = HW </li></ul><ul><li>174 – 144 =  30  mph </li></ul>
 
 
<ul><li>Head-wind component:  30  mph </li></ul><ul><li>Cross-wind component:  47  mph </li></ul>
 
Answer <ul><li>Wind from  118º  at  55  mph </li></ul>
6.TRUE COURSE (TRACK) AND GROUND SPEED <ul><li>Given: </li></ul><ul><ul><li>TAS 156 mph </li></ul></ul><ul><ul><li>MH 289º...
 
 
 
<ul><li>Left crosswind component:  39  mph </li></ul><ul><li>WCA:  14º </li></ul>
 
 
 
<ul><li>It now appears that the first WCA of 14º was 1º too much (the new one is  13 º) </li></ul><ul><li>Back off 1º of t...
 
<ul><li>The crab angle is greater than 10º (13º), it is necessary to use “effective TAS” </li></ul>
 
 
<ul><li>17 mph tailwind component </li></ul><ul><li>ETAS + TW = GS </li></ul><ul><li>152 +17 =  169  mph </li></ul><ul><li...
7.TRUE HEADING AND TRUE AIR SPEED <ul><li>Given: </li></ul><ul><ul><li>TC 56º </li></ul></ul><ul><ul><li>Desired GS 166 kt...
 
 
<ul><li>Desired GS: 166 kts </li></ul><ul><li>Headwind component: 20 kts </li></ul><ul><li>The TAS (or effective): 166 + 2...
 
 
<ul><li>The WCA is greater than 10º </li></ul><ul><li>Move the bottom disc till 186 is opposite  12º  on the black scale (...
 
 
<ul><li>Note that the TAS index points to 19 </li></ul><ul><li>The wind is from the right TC + CA = TH  or ….. </li></ul>
 
8.OFF-COURSE CORRECTION <ul><li>Given: </li></ul><ul><li>- Miles flown:  40 </li></ul><ul><li>- Miles off course:  5 </li>...
 
<ul><li>7º is the number of degrees you must correct your heading in order to parallel your intended course </li></ul><ul>...
 
 
<ul><li>You must decide whether the next correction should be 18º or 2º </li></ul><ul><li>Common sense will tell you that ...
Answer: <ul><li>7º + 2º =  9º </li></ul>
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6. CR-3 Wind Side 2/2

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Second part of the presentation shown in class abot the CR-3 Wind side

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6. CR-3 Wind Side 2/2

  1. 1. CR-3 Computer Wind Side 2/2
  2. 2. 5.FINDING WINDS IN FLIGHT <ul><li>Given: </li></ul><ul><ul><li>TAS 180 mph </li></ul></ul><ul><ul><li>TC 175º </li></ul></ul><ul><ul><li>TH 160º </li></ul></ul><ul><ul><li>GS 144 mph </li></ul></ul><ul><li>Find: Actual W/V </li></ul>
  3. 4. <ul><li>TC – TH = WCA </li></ul><ul><li>175º – 160º = 15º </li></ul><ul><li>WCA is 15º Left. Determine the “effective” TAS </li></ul>
  4. 6. <ul><li>ETAS = 174 mph </li></ul><ul><li>ETAS – GS = HW </li></ul><ul><li>174 – 144 = 30 mph </li></ul>
  5. 9. <ul><li>Head-wind component: 30 mph </li></ul><ul><li>Cross-wind component: 47 mph </li></ul>
  6. 11. Answer <ul><li>Wind from 118º at 55 mph </li></ul>
  7. 12. 6.TRUE COURSE (TRACK) AND GROUND SPEED <ul><li>Given: </li></ul><ul><ul><li>TAS 156 mph </li></ul></ul><ul><ul><li>MH 289º </li></ul></ul><ul><ul><li>Var. 7ºW </li></ul></ul><ul><ul><li>W/V 180º /40 mph </li></ul></ul><ul><li>Find: </li></ul><ul><ul><li>TC </li></ul></ul><ul><ul><li>GS </li></ul></ul>
  8. 16. <ul><li>Left crosswind component: 39 mph </li></ul><ul><li>WCA: 14º </li></ul>
  9. 20. <ul><li>It now appears that the first WCA of 14º was 1º too much (the new one is 13 º) </li></ul><ul><li>Back off 1º of the adjustment, making a true course reading of 295º </li></ul><ul><li>The crosswind component is still 36 </li></ul><ul><li>The TC is 295º </li></ul>
  10. 22. <ul><li>The crab angle is greater than 10º (13º), it is necessary to use “effective TAS” </li></ul>
  11. 25. <ul><li>17 mph tailwind component </li></ul><ul><li>ETAS + TW = GS </li></ul><ul><li>152 +17 = 169 mph </li></ul><ul><li>True course = 295º </li></ul>
  12. 26. 7.TRUE HEADING AND TRUE AIR SPEED <ul><li>Given: </li></ul><ul><ul><li>TC 56º </li></ul></ul><ul><ul><li>Desired GS 166 kts </li></ul></ul><ul><ul><li>Wind 120º/45kts </li></ul></ul><ul><li>Find: </li></ul><ul><ul><li>TAS </li></ul></ul><ul><ul><li>TH </li></ul></ul>
  13. 29. <ul><li>Desired GS: 166 kts </li></ul><ul><li>Headwind component: 20 kts </li></ul><ul><li>The TAS (or effective): 166 + 20 = 186 kts </li></ul>
  14. 32. <ul><li>The WCA is greater than 10º </li></ul><ul><li>Move the bottom disc till 186 is opposite 12º on the black scale (effective TAS) </li></ul><ul><li>Check to see that the 40-knot crosswind component on the outer scale is still close to 12º on the inner scale </li></ul>
  15. 35. <ul><li>Note that the TAS index points to 19 </li></ul><ul><li>The wind is from the right TC + CA = TH or ….. </li></ul>
  16. 37. 8.OFF-COURSE CORRECTION <ul><li>Given: </li></ul><ul><li>- Miles flown: 40 </li></ul><ul><li>- Miles off course: 5 </li></ul><ul><li>- Miles to destination: 160 </li></ul><ul><li>Find: Degrees correction to heading to reach destination directly </li></ul>
  17. 39. <ul><li>7º is the number of degrees you must correct your heading in order to parallel your intended course </li></ul><ul><li>It is now necessary to find the number of degrees additional correction needed to reach your destination </li></ul>
  18. 42. <ul><li>You must decide whether the next correction should be 18º or 2º </li></ul><ul><li>Common sense will tell you that 2º </li></ul><ul><li>Remember the rule that 1º of drift will give approximately 1 mile off course in 60 </li></ul>
  19. 43. Answer: <ul><li>7º + 2º = 9º </li></ul>

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