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6. CR 3 Wind Side 1/2
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6. CR 3 Wind Side 1/2

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Transcript

  • 1. CR-3 Computer Wind Side 1 /2
  • 2. 1.Given TAS, TC and W/V
    • TAS = 110 kt
    • TC = 090º
    • W/V = 310º / 30 kt
    • Find:
      • HW or TW
      • CW (left or right)
      • WCA
      • HDG
      • GS
  • 3.  
  • 4.  
  • 5.
    • TW = 23 kt
    • GS = TAS + TW = 110 + 23 = 133 kt
    • CW = -20 kt (left)
  • 6.  
  • 7.
    • WCA = -10.5º (left)
    • HDG = TC + WCA = 090º - 10.5º =079.5º
  • 8. 2.Given WCA, TAS, GS & TC
    • TAS = 120 kt
    • WCA = -8º (left)
    • GS = 100
    • TC = 200º
    • Find:
      • HDG
      • HW or TW
      • CW (left or right)
      • W/V
  • 9.
    • GS – TAS = 100 – 120 = -20 (HW)
    • HDG = TC + WCA = 200º - 8º = 192º
  • 10.  
  • 11.  
  • 12.
    • CW = -17 kt (left)
  • 13.  
  • 14.  
  • 15.
    • W/V = 157º / 27 kt
  • 16. 3.FORECAST WINDS
    • Given:
      • TAS 180 mph
      • M Course 140º
      • Variation 10º W
      • W/V 100º / 40 mph
    • Find:
      • WCA
      • MH
      • GS
  • 17.  
  • 18.  
  • 19.  
  • 20.
    • 140º - 6º = 134º M H
  • 21.  
  • 22.
    • TAS – HW = GS
    • 180 – 35 = 145 mph
  • 23. Answer:
    • WCA = 6º left
    • M H = 134º
    • GS = 145 mph
  • 24. 4.Forecast winds 2 nd leg
    • Given:
      • TAS 180 mph
      • MC 186º
      • Variation 11º W
      • W/V 100º/40 mph
    • Find:
      • WCA
      • MH
      • GS
  • 25.  
  • 26.  
  • 27.  
  • 28.
    • M C – WCA (L) = M H
    • 186º - 12º = 174º
  • 29.
    • TAS – H W = GS
    • But WCA exceeds 10º (12º)
    • Use ETAS
  • 30.  
  • 31.
    • TAS – HW = GS
    • 176 – 10 = 166 mph
  • 32. Answer:
    • WCA = 12º
    • MH = 174º
    • GS = 166 mph