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Luas kerucut 03
Luas kerucut 03
Luas kerucut 03
Luas kerucut 03
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Luas kerucut 03

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Presentasi Menemukan Luas Kerucut

Presentasi Menemukan Luas Kerucut

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  • 1. c. Luas sisi kerucut 1. Luas selimut kerucut TRR’ Luas juring TRR’ = Luas selimut kerucut = π r s 2. Luas sisi kerucut = L. Selimut + L. Alas L = π r s + L = π r ( s + r ) S = garis pelukis Luas Juring TRR 1 = Luas juring TRR 1 = π r s r R’ T R s s
  • 2. Contoh soal 1 Sebuah kerucut mempunyai alas berdiameter 12 cm. Apabila panjang garis pelukis 10 cm, hitunglah luas permukaan kerucut itu. Jawab : Diketahui : d = 12 cm, maka r = 6 cm s = 10 cm <ul><li>Luas selimut kerucut = π rs </li></ul><ul><li>= x 6 x 10 cm 2 </li></ul><ul><li>= 188 cm 2 </li></ul><ul><li>Luas alas kerucut = π r 2 </li></ul><ul><li>= x 6 2 cm 2 </li></ul><ul><li>= 113 cm 2 </li></ul><ul><li>Luas permukaan kerucut = 188 cm 2 + 113 cm 2 </li></ul><ul><li>= 301 cm 2 </li></ul>Jadi luas permukaan kerucut adalah 301 cm 2
  • 3.  
  • 4. Contoh soal 3 Luas selimut kerucut 264 cm 2. jika jari-jari alas kerucut 6 cm. Hitunglah panjang garis pelukis dan tinggi kerucut tersebut ( π = ) Jawab : <ul><li>Luas selimut jerucut = π r s </li></ul><ul><li>264 = . 6 . S </li></ul><ul><li>S = = 14 cm </li></ul>Panjang garis pelukis <ul><li>Misal tinggi kerucut = t, maka : </li></ul><ul><li>t 2 = s 2 – r 2 </li></ul><ul><li>= (14) 2 – 6 2 </li></ul><ul><li>= 160 </li></ul><ul><li>t = √160 = 4√10 </li></ul>Jadi tinggi kerucut adalah 4√10 cm

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